1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
amm1812
3 years ago
14

Solve the equation. 9x108

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

972

Step-by-step explanation:

9x8 = 72

9x 100 = 900

(you can use a calculator)

You might be interested in
Erin's water bottle holds 600 ml of water.dylans water bottle holds 1 l of water. whose water bottle has the greater capacity?ho
Lapatulllka [165]
Dylans water bottle is greater by 400 ml
4 0
3 years ago
Based on Pythagorean identities, which equation is true? A. Sin^2 theta -1= cos^2 theta B. Sec^2 theta-tan^2 theta= -1 C. -cos^2
Arturiano [62]

Answer:

D

Step-by-step explanation:

our basic Pythagorean identity is cos²(x) + sin²(x) = 1

we can derive the 2 other using the listed above.

1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)

1 + tan²(x) = sec²(x)

2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)

cot²(x) + 1 = csc²(x)

A. sin^2 theta -1= cos^2 theta

this is false

cos²(x) + sin²(x) = 1

isolating cos²(x)

cos²(x) = 1-sin²(x), not equal to sin²(x)-1

B. Sec^2 theta-tan^2 theta= -1

1 + tan²(x) = sec²(x)

sec²(x)-tan(x) = 1, not -1

false

C. -cos^2 theta-1= sin^2

cos²(x) + sin²(x) = 1

sin²(x) = 1-cos²(x), our 1 is positive not negative, so false

D. Cot^2 theta - csc^2 theta=-1

cot²(x) + 1 = csc²(x)

isolating 1

1 = csc²(x) - cot²(x)

multiplying both sides by -1

-1 = cot²(x) - csc²(x)

TRUE

3 0
3 years ago
Write the equation of the line in point-slope form of the given point and slope. This is an essay style question. If you hit the
svp [43]

Answer:

<h3>y + 2 = 3/7(x-7)</h3>

Step-by-step explanation:

The point-slope form of the equation will be expressed as;

y - y0 = m(x-x0) where;

m is the slope

(x0, y0) is the point on the line

Given

Slope m = 3/7

Point (x0, y0) = (7, -2)

Substitute into the equation;

y - y0 = m(x-x0)

y - (-2) = 3/7 (x - 7)

<em>y + 2 = 3/7(x-7)</em>

<em>Hence the equation in point-slope form is y + 2 = 3/7(x-7)</em>

3 0
3 years ago
A new computer can complete a complex biochemistry calculation in 7 hours less than an older-model computer. Working together, t
Alchen [17]
The rate a computer works is 1/time. Working together, you add the rates.
Let new computer be x, old computer be y.
x = y - 7

\frac{1}{x} + \frac{1}{y} = \frac{1}{13} \\  \\ \frac{1}{y-7}+\frac{1}{y} = \frac{1}{13} \\  \\ \frac{2y-7}{y(y-7)} = \frac{1}{13} \\  \\ y(y-7) = 13(2y-7) \\  \\ y^2-33y+91 = 0 \\  \\ y = 29.96 \\  \\ x = y-7 = 29.96-7 = 22.96
Rounded to nearest tenth gives:
x = 23 hours
6 0
3 years ago
Aisha is trying to determine if △LMN and △PQR are similar, congruent, or neither using the information in the diagram.
Digiron [165]

Answer:

option D is the correct ans.

Step-by-step explanation:

They are similar by SSS axiom as the correspoding angles are proportional....

HOPE IT HELPS YOU!!!!!

3 0
3 years ago
Read 2 more answers
Other questions:
  • Which expression below is equivalent to 2x + 8?
    11·1 answer
  • Please.<br>solve the system of equations
    12·1 answer
  • Can you answer this? <br> factorise 6p + 24q
    6·1 answer
  • #1 Describe the translation of the point to its image.<br> (-15, 22) - (25, 15)<br> type here
    13·1 answer
  • Complete the equation and solve the problem. Let n be the number of students in each row. There are 37 students in the marching
    7·2 answers
  • Nurse Jackson examines immunization records for this past winter at the
    6·2 answers
  • Slope 0; through (-5, -1)<br> with steps please.
    12·1 answer
  • A coin is tossed four times. What is the probability of getting tails four times in a row?
    6·1 answer
  • CAN YOU ANSWER THIS QUESTION
    5·1 answer
  • Calculate the perimeter of this shape.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!