Answer:
∠AOB = 112°
Step-by-step explanation:
mentally draw line segment OC
that line bisects 124° so ∠OCB = 1/2(124°) = 62°
ΔOCB is isosceles because OB = OC
∠OBC = 62° because it is equal to ∠OCB
all triangle interior angles add up to 180°
∠BOC = 180° - 62° - 62° = 56°
∠AOC = 56° because OC was a bisector of ∠AOB
∠AOB = 56° + 56° = 112°
It’s an exponential function
What? What two? lol maybe i can slove it
Answer:
120°
Step-by-step explanation:
Area of a sector is:
A = πr² (θ/360°)
Plugging in values and solving:
49/3 π = π (7)² (θ/360°)
49/3 π = 49π (θ/360°)
1/3 = θ/360°
θ = 120°
Answer:
ĐÉO OKF
Step-by-step explanation:
