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NeTakaya
3 years ago
13

Can you help me solve these 2?

Mathematics
2 answers:
makvit [3.9K]3 years ago
4 0
What? What two? lol maybe i can slove it
xxTIMURxx [149]3 years ago
3 0

Answer:

hamood backwards

Step-by-step explanation:

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Can someone tell me the points please that’s all
djverab [1.8K]

Answer:

(From left-right)

-10, 8

-8, 7

-6, 6

-4, 5

-2, 4

0, 3

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Step-by-step explanation:

7 0
3 years ago
Find three consecutive integers such that the sum of the first and twice the second is 80 minus three times the third
ivanzaharov [21]

Answer:

The three consecutive integers are 12, 13, 14.

Step-by-step explanation:

Encode the question in an equation. We are given two facts: (1) the three integers are consecutive, and (2) they relate to each other through a sum.

Pick any of the integers (first, second, or third) and call it n. Then write the two others correspondingly in terms of n. I pick the middle one as n, so the three consecutive integers are (n-1), n, (n+1). That's (1). As for (2), here is the fact:

(n-1)+2n = 80-3(n+1)

Lo and behold, one equation with one unknown! Easy to solve for n to give us  the middle integer, n:

(n-1)+2n = 80-3(n+1)\\3n-1= 80-3n -3\\6n =78\\n = 13

The three consecutive integers are 12, 13, 14.

3 0
4 years ago
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3 years ago
Estimate the value of 50.75×0.18
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The answer is to be 9.135
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