Answer:
Step-by-step explanation:
.
It is apparently obvious we could expand the bracket and integrate term-by-term. This method would work but is very time consuming (and you could easily make a mistake) so we use a different method: integration by substitution.
Integration by substitution involves swapping the variable 
for another variable which depends on x: 
. (We are going to choose 
for this question).
The very first step is to choose a suitable substitution. That is, an equation 
which is going to make the integration easier. There is a trick for spotting this however: if an integral contains both a term and it's derivative then use the substitution 
.
Your integral contains the term 
. The derivative is 
and (ignoring the constants) we see is also in the integral and so the substitution 
will unravel this integral!
Step 2: We must now swap the variable of integration from x to u. That means interchanging all the x's in the integrand (the term being integrated) for u's and also swapping (dx" to "du").
Then,
.
The substitution has made this integral is easy to solve!
Finally we can substitute back to get the answer in terms of x:
The formula for the area of a hexagon is
![A=\frac{3\sqrt[]{3}}{2}s^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B3%5Csqrt%5B%5D%7B3%7D%7D%7B2%7Ds%5E2)
where 's' is the length of one side of the regular hexagon.
The side of our regular hexagon is 2 feet, therefore, its area is
![\begin{gathered} A=\frac{3\sqrt[]{3}}{2}\cdot(2)^2=6\sqrt[]{3} \\ 6\sqrt[]{3}=10.3923048454\ldots\approx10 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%5Cfrac%7B3%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot%282%29%5E2%3D6%5Csqrt%5B%5D%7B3%7D%20%5C%5C%206%5Csqrt%5B%5D%7B3%7D%3D10.3923048454%5Cldots%5Capprox10%20%5Cend%7Bgathered%7D)
The exact area of the hexagon is 6√3 ft², which is approximately 10 ft².
Answer:
C
Step-by-step explanation:
Answer:
86.7%
Step-by-step explanation:
For questions regarding values related to a normal distribution, a suitable calculator is required. Numerous calculators, apps, web sites, and spreadsheets are capable of answering this question.
__
One standard deviation above the mean is 327 +27 = 354, so the value is expected to be slightly more than 50% +34% = 84%. It is no surprise, then, that a calculator tells you 86.7% of the data is below 857.
_____
<em>Additional comment</em>
The "empirical rule" tells you 68% of the area is within 1 standard deviation of the mean. The distribution is symmetrical, so half that, 34%, is between the mean and 1 standard deviation above the mean. Of course, 50% of the data is below the mean.
