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Tomtit [17]
3 years ago
6

Please help!!!!!!!!! Anthony is preparing to paint a large shipping container and needs to calculate the area of the container s

o he can buy the correct amount of paint. The equation he uses to find the area, A, in square feet is A= 2( lw + wh + lh) where l is the length, w is the width, and h is the height The container is 8 feet wide, 12 feet high, and 24 feet long. What is the area of the container in square feet? Answer choices: A. 567, B. 1152, C. 2304, D. 4608
Mathematics
2 answers:
irinina [24]3 years ago
6 0

Answer: I need help too to that

Step-by-step explanation:

zepelin [54]3 years ago
4 0

Answer: 1,152

Step-by-step explanation:

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How is this solved using trig identities (sum/difference)?
GenaCL600 [577]
FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

cos \beta = -\frac{1}{2}  \sqrt{3}

tan \beta= \frac{1}{3}  \sqrt{3}

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2}  \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )
sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )
sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )
cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )
cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )

Find tan (α - β)
tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha  tan \beta }
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}

Simplify the denominator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5\sqrt{3}}{24})}
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the numerator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }
tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the fraction
tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})
tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}

7 0
3 years ago
Michael is 12 yrs older than Ava. The sum of their ages are 38. What are their ages?
Setler [38]
She is 26 years old because you need to do 38 - 12=26!
5 0
3 years ago
Find the area of an equilateral triangle if a side is 8 times the square root of 3
irga5000 [103]

The area would be about 83.14.

You can find this by starting with the formula for the area of an equilateral triangle:

A = \frac{\sqrt{3}}{4}  S^{2}

In this equation, A is the area and S is the side. So we'll just plug in the value.

A = \frac{\sqrt{3}}{4}  S^{2}

A = \frac{\sqrt{3}}{4} (8\sqrt{3})^{2}

A = \frac{\sqrt{3}}{4}  24

A = 83.14

4 0
3 years ago
Describe two different cross section shapes that can be formed by slicing a cylinder. For each shape describe how the cross sect
artcher [175]

either a rectangle or circle will be made. If you cut it horizontially you will get a circle. Vertically and you will have a rectangle

5 0
3 years ago
There are 400 seats in the Jefferson Middle School auditorium. The students are using 35 of the seats. There are 65 seats being
jolli1 [7]

Answer:

300

Step-by-step explanation:

400 - 35 - 65 = 300

100 seats being used, so 300 seats left unused

(Btw, do you happen to know of a certain Northeast Middle School at all?)

6 0
4 years ago
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