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Pani-rosa [81]
2 years ago
11

Can someone help me with my problems

Mathematics
1 answer:
Molodets [167]2 years ago
4 0

Answer:

while multiplying or dividing both side by a negative number we have to change the side of inequality sign. so u have to write r greater then -24

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Find the value of x<br><br> 2+4( 3 + 2x ) = 3x + 8
solniwko [45]
2 + 4(3+2x) = 3x + 8

2 + 12 + 8x = 3x + 8

14 - 8 = 3x - 8x

6 = -5x

x = -6/5
8 0
3 years ago
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What is thesum of the two polynomials ? (-x^2+9)+(-3x^2-11x+4)
True [87]
-x^2 + 9 - 3x^2 - 11x + 4
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3 0
3 years ago
HELP!!!!!!!
anygoal [31]

Answer:

Sample Response: First, the like terms had to be combined using the lowest common denominator (LCD). Then the subtraction property of equality was used to isolate the variable term. Finally, both sides of the equation were multiplied by the reciprocal of the coefficient to solve for a.

Step-by-step explanation:

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3 years ago
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G verify that the divergence theorem is true for the vector field f on the region
Alenkasestr [34]
\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1

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\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi

On the other hand, we can parameterize the boundary of E by

\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle

with 0\le u\le2\pi and 0\le v\le\pi. Now, consider the surface element

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv
=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi

as required.
3 0
3 years ago
there are fewer than 8 gallons of gas in the tank... write an inequality to represent each situation.
matrenka [14]

Answer:

x<8

Step-by-step explanation:

i don't think the question was complete, i cannot make an inequality with just the information given.

5 0
2 years ago
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