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3 years ago

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In the figure below AB is a diameter of circle P. What is the arc measure of minor arc AC in degrees?

1 answer:

arlik [135]3 years ago

3 0

Answer:

$P = 139$

Step-by-step explanation:

See attachment for complete question

Required

Determine measure of Arc length AC

The interpretation of this question is to find P

If AB is the diameter, then

$P + 41 = 180$

$P + 41 - 41= 180 - 41$

$P = 139$

<em>Hence, the measure is 139 degrees</em>

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Use the formula L= 10 log 10 R, where Is the loudness of a sound and R is the sound's relative intensity. to find out how much l

WINSTONCH [101]

Answer:

$X=24.1decibels$

Step-by-step explanation:

From the question we are told that:

Loudness function $L= 10 log_{10} R$

Sound of a person $S_p=80\ decibels\ or 10^8$

Number of persons talking $n=20 people$

Generally the Relative intensity for 20 people is mathematically given by

Relative intensity for $R_{20}=$ $20*10^8$

Relative intensity for $R_{20}=$ $20^8$

Generally the loudness for 20 people is mathematically given by

$L_{20}= 10 log_{10} R$

$L_{20}= 10 log_{10} 20^8$

$L_{20}= 10 (8 log_{10} 20)$

$L_{20}= 104.1 decibels$

Therefore increase in loudness X is given as

$X=104.1-80=-52.90$

$X=24.1decibels$

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2 years ago

According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : $P(X=r) =^nC_r p^r q^{n-r}$

At x = 2

$P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}$

$P(X=2) =8.8009 \times 10^{-7}$

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=0.2360$

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3 years ago

five out of eight bags of m&ms had exactly 32 pieces in them. how many bags out of 40 should have exactly 32 pieces

vodka [1.7K]

Yo, your answer is gonna be 25 my dude

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13(x - 3)=39 what is answer

artcher [175]

X = 6 after distributing then adding 39 to both sides and then divide by 13

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A wheelchair access ramp has an angle of elevation of 41 degrees. If the ramp reaches to the top of a 26 inch high porch, how lo

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Answer:

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Step-by-step explanation:

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