X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8
Answer:
(-7, 1)
Step-by-step explanation:
Add the x and y values separately which is across from your screen to get the function which is (-7, 1).
Answer:
52feet
Step-by-step explanation:
The set up will be a right angle
Let the angle of depression be 30°
The height above the sea level will be the opposite
The distance of the ship from the base is x (adjacent)
Using TOA
Tan theta = opposite/adjacent
Tan 30 = 30/x
x = 30/tan 30
x = 30/0.5774
x = 51.96
x ≈ 52 feet to the nearest foot
Let's factor the top and the bottom.
Top factors 4x + 20 = 4(x + 5)
Bottom x^2 + 2x - 15 = (x + 5)(x - 3)
The gcf is the largest value that will go into both the top and the bottom. In our problem the ONLY thing that will go into top and bottom is x + 5 so that is your GCF. (c)
As an opportunity to respond to people who might disagree with your claim.
