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Debora [2.8K]
3 years ago
8

If it is warm outside, then I will not wear my jacket.

Mathematics
2 answers:
Oliga [24]3 years ago
5 0
1. Let the statements and their denials be given as follows:

p: it is warm outside                      p': it is not warm outside
q: I will not wear my jacket            q': I will wear my jacket

2. The statement can be described as p⇒q, so its inverse is p'⇒q', which is the statement"<span>If it is not warm outside, then I will wear my jacket.</span>"


andreev551 [17]3 years ago
3 0

Answer:

hbfhabfsdkbfkuajg ferbvfwqfyuwbfgwjvfgwevfuvbfgwrvfwerfvjwhevfbwjehvfgwevfwevfhwdbhvjbdhvberhfbrwebfhwerbfewhjfbwe

Step-by-step explanation:

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What is 874 divided by 23
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874 Divided by 23 = 38.

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8 0
3 years ago
George is making a triangular enclosure in his yard. He plans on using two old fence posts as vertices, and will place a new
Genrish500 [490]

Answer:

The correct answers for the possible locations for the are;

(-9, 1)

(0, 0)

Step-by-step explanation:

The coordinates of two of the three posts are given in feet as (-5, 4) and (2, 6)

The length of the available fencing = 25 feet

The length, l, of the segment between the coordinates of the two old posts vertices of the fence is given by the following equation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) = (-5, 4)

(x₂, y₂) = (2, 6)

l = \sqrt{\left (6-4  \right )^{2}+\left (2-(-5)  \right )^{2}} = \sqrt{53} \approx 7.25 \ feet

Given the coordinates of the third point as (x₃, y₃), we have;

Therefore, we have;

\sqrt{\left (y_{3}-4  \right )^{2}+\left (x_{3}-(-5)  \right )^{2}} +  \sqrt{\left (y_{3}-6  \right )^{2}+\left (x_{3}-(2)  \right )^{2}} = 25 - \sqrt{53}

For the point (2, 6), we have;

\sqrt{\left ((-6)-4  \right )^{2}+\left (2-(-5)  \right )^{2}} +  \sqrt{\left ((-6)-6  \right )^{2}+\left (2-(2)  \right )^{2}} = 24.2 > 25-\sqrt{53}

For the point (-9, 1), we have;

\sqrt{\left ((-6)-4  \right )^{2}+\left (2-(-5)  \right )^{2}} +  \sqrt{\left ((-6)-6  \right )^{2}+\left (2-(2)  \right )^{2}} = 17.08 < 25-\sqrt{53}

For the point (0, 0), we have;

\sqrt{\left ((0)-4  \right )^{2}+\left (0-(-5)  \right )^{2}} +  \sqrt{\left ((0)-6  \right )^{2}+\left (0-(2)  \right )^{2}} = 12.73 < 25-\sqrt{53}

For the point (8, 8), we have;

\sqrt{\left ((8)-4  \right )^{2}+\left (8-(-5)  \right )^{2}} +  \sqrt{\left ((8)-6  \right )^{2}+\left (8-(2)  \right )^{2}} = 19.92 > 25-\sqrt{53}

For the point (-4, -5), we have;

\sqrt{\left ((-5)-4  \right )^{2}+\left ((-4)-(-5)  \right )^{2}} +  \sqrt{\left ((-5)-6  \right )^{2}+\left ((-4)-(2)  \right )^{2}} = 22.04 > 25-\sqrt{53}

Therefore, the correct answers for the possible locations for the are (-9, 1) and (0, 0).

7 0
4 years ago
Find the solutions to the equation below check all that apply
11111nata11111 [884]

A. x=1/3

B. x=-4/3

_____________________________________________________

Solve for x over the real numbers: using the factor method:

9 x^2 + 9 x - 4 = 0

The left hand side factors into a product with two terms:

(3 x - 1) (3 x + 4) = 0

Split into two equations:

3 x - 1 = 0 or 3 x + 4 = 0

Add 1 to both sides:

3 x = 1 or 3 x + 4 = 0

Divide both sides by 3:

x = 1/3 or 3 x + 4 = 0

Subtract 4 from both sides:

x = 1/3 or 3 x = -4

Divide both sides by 3:

Answer:  x = 1/3 or x = -4/3

7 0
3 years ago
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