Answer:
See Explanation
Step-by-step explanation:
Given

Required
Determine the number of cans for the wall
The dimension of the wall is not given. So, I will use the following assumed values:


First, calculate the area of the wall



If 
Then 
Cross Multiply:



Make x the subject


400 cans using the assume dimensions.
So, all you need to to is, get the original values and follow the same steps
Triangle ABC is congruent to triangle CDE using the side - angle - side congruence theorem. The sink hole is 52.2 ft and the Perimeter of ABC is 172.2 ft
<h3>What are
congruent triangles?</h3>
Two triangles are said to be congruent if they have the same shape and their corresponding sides are congruent.
In the image shown:
AC = CE, BC = ED and they have the same angle (opposite angles are congruent).
Hence:
Triangle ABC is congruent to triangle CDE using the side - angle - side congruence theorem.
AB = DE = 52.2 ft
Perimeter of ABC = AB + BC + AC = 50 + 70 + 52.2 = 172.2 ft
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Answer:
3*10=30.
Step-by-step explanation:
increased by 3% each year for 10 years
increased 30%.
0.31*0.30= .92
Its d) f(x)= 300+50x/2+x..............................................................................
Each of the pairs of the opposite angles made by two intersecting lines are called vertical angles. The correct option is A.
<h3>What are vertical angles?</h3>
Each of the pairs of the opposite angles made by two intersecting lines are called vertical angles.
The proof can be completed as,
Given the information in the figure where segment UV is parallel to segment WZ.: Segments UV and WZ are parallel segments that intersect with line ST at points Q and R, respectively. According to the given information, segment UV is parallel to segment WZ, while ∠SQU and ∠VQT are vertical angles. ∠SQU ≅ ∠VQT by the Vertical Angles Theorem. Because ∠SQU and ∠WRS are corresponding angles, they are congruent according to the Corresponding Angles Theorem. Finally, ∠VQT is congruent to ∠WRS by the Transitive Property of Equality.
Hence, the correct option is A.
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