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Ilya [14]
3 years ago
13

Please answer these questions! Need help!

Mathematics
1 answer:
astra-53 [7]3 years ago
3 0

Answer:

Question 2  is $500 and Question 3 is 5

Step-by-step explanation:

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You receive 9 text messages in 12 minutes. What is the rate of text messages per hour?
joja [24]
If you get 9 text messages in 12 min, you can get the answer by multiplying the amount of message with 60 minutes (as the time unit is in minute) so and then divide it by 12 as shown below. 
9×60÷12 = 45 text messages 
7 0
3 years ago
Which of the following is equivalent to (8 – 5) ÷ 23 ?
Oksanka [162]
(8 - 5) ÷ 23

= \frac{(8 - 5)}{23}

= \frac{3}{23}
4 0
2 years ago
Solve and show work <br> What is 10% of 40
Daniel [21]
10% of 40 is 4.

1% of 40 = 40/100 = 0.4.

10% of 40 = 10.

Write 10% as a decimal number = 10% = 10/100 = 0.1

Multiply 0.1 by 40 = 0.1 × .40 = 4
8 0
3 years ago
Read 2 more answers
1. Carissa also has a sink that is shaped like a half-sphere. The sink has a volume of 2000/3 π inches. One day, her sink clogge
Anettt [7]

Answer:

Yes, your answers are correct.

The volume of a cone is given by V = 1/3πr²h.  Since the diameter of the first cone is 4, the radius is 2; therefore the volume is

V = 1/3π(2²)(8) = 32π/3

We divide the volume of the sink, 2000π/3, by the volume of the cone:

2000π/3 ÷ 32π/3 = 2000π/3 × 3/32π = 6000π/96π = 62.5 ≈ 63.

The diameter of the second conical cup is 8, so the radius is 4.  The volume then is:

V = 1/3π(4²)(8) = 128π/3

Dividing the volume of the sink, 2000π/3, by 128π/3:

2000π/3 ÷ 128π/3 = 2000π/3 × 3/128π = 6000π/384π = 15.625 ≈ 16

7 0
3 years ago
Find the diagonal of a rectangular frame which measures 77 in. by 36 in.
Cerrena [4.2K]

Answer:

85

Step-by-step explanation:

think about the diagonal of the frame, breaking up a rectangle into 2 right angled triangles. we are already given the legs of the triangle (77, and 36) and now we have to solve fro the hypotenuse (or the diagonal). so use pythagorean theorem :

77^2 + 36^2 = c^2

7225 = c^2

c = 85

5 0
3 years ago
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