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Hitman42 [59]
3 years ago
15

Divide 25 1858. To find the quotient, start by dividing

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0

Answer:

74.32

Step-by-step explanation:

1,858 divided by 25= 74.32

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Which function grows the fastest for large values of x? f(x)=8x f(x)=3x f(x)=4x2+3 f(x)=1.5x 20 points
Aleonysh [2.5K]
The 4 functions are:
f_1 (x) = 8x
f_2(x)=3x
f_3(x)=4x^2+3
f_4(x)=1.5 x

Let's keep in mind that for large values of x, a quadratic function grows faster than a linear function:
ax^2 \ \textgreater \  kx for large values of x

In this problem, we can see that the only quadratic function is f_3(x), while all the others are linear functions, so the function that grows faster for large values of x is
f_3(x) = 4x^2 +3
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3 years ago
The odds that a child entering a convenience store with her parents will not get a package of cupcakes are 1 to 11. what is the
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P(get a package of cupcakes) = 11/12


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3 years ago
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A sports store is having a 20% off sale on skis. The original price of the ski is $560.00
attashe74 [19]

Answer:

Total cost: 486.080$

Step-by-step explanation:

Original Price: 560.000$

Sale: 20%

Discount: 560.000$ * 20% = 112.000$

Discounted Price: 560.000$ - 112.000$ = 448.000$

Tax Rate: 8.5%

Tax: 448.000$ * 8.5% = 38.080$

Tax after Tax: 448.000$ + 38.080$ = 486.080$

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2 years ago
Quiana took out a loan to pay for a new car initially she owed the lender 15,234.68. she has repaid 247.43 of the loan each mont
kykrilka [37]

Given Information:

Initial amount of loan = $15,234.68

Monthly payment = $247.43

Number of months = 5

Required Information:

Net change in loan = ?

Answer:

Net change in loan = $1,237.15 = $1,237(3/20)

Step-by-step explanation:

Quiana owed her lender an amount of 15,234.68 initially, she repaid the lender each month with an amount of $247.43 for 5 months, so the total amount that she repaid is

Total amount repaid = Monthly payment*Number of months

Total amount repaid = $247.43 × 5

Total amount repaid = $1,237.15

The remaining owed amount is given by

Balance = Initial amount of loan - Total amount repaid

Balance = $15,234.68 - $1237.15

Balance = $13,997.53

So the net change to the loan from Quiana's perspective over the past 5 months is,

Net change in loan = Initial amount of loan - Balance

Net change in loan = $15,234.68 - $13,997.53

Net change in loan = $1,237.15

or

Net change in loan = $1,237(3/20)

Therefore, the net change to the loan from Quiana's perspective over the past 5 months is $1,237.15

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3 years ago
Find the approximate circumference of a circle with a diameter of 80 yards.
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<em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em>

<em>Sol</em><em>ution</em><em>,</em>

<em>Diameter</em><em> (</em><em>d</em><em>)</em><em>=</em><em>8</em><em>0</em><em> </em><em>yards</em>

<em>Radius</em><em>(</em><em>r</em><em>)</em><em>=</em><em>8</em><em>0</em><em>/</em><em>2</em><em>=</em><em>4</em><em>0</em><em> </em><em>yards</em>

<em>Circum</em><em>ference</em><em> </em><em>of</em><em> </em><em>circle</em><em>=</em><em>?</em>

<em>Now</em><em>,</em>

<em>Circ</em><em>umference</em><em> </em><em>of</em><em> </em><em>circle</em><em>=</em><em>2</em><em> </em><em>pi</em><em> </em><em>r</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>*</em><em>3</em><em>.</em><em>1</em><em>4</em><em>*</em><em>4</em><em>0</em>

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<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

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