Answer:
Region D.
Step-by-step explanation:
Here we have two inequalities:
y ≤ 1/2x − 3
y < −2/3x + 1
First, we can see that the first inequality has a positive slope and the symbol (≤) so the values of the line itself are solutions, this line is the solid line in the graph.
And we have that:
y ≤ 1/2x − 3
y must be smaller or equal than the solid line, so here we look at the regions below the solid line, which are region D and region C.
Now let's look at the other one:
y < −2/3x + 1
y = (-2/3)*x + 1
is the dashed line in the graph.
And we have:
y < −2/3x + 1
So y is smaller than the values of the line, so we need to look at the region that is below de dashed line.
The regions below the dashed line are region A and region D.
The solution for the system:
y ≤ 1/2x − 3
y < −2/3x + 1
Is the region that is a solution for both inequalities, we can see that the only region that is a solution for both of them is region D.
Then the correct option is region D.
Using the rule (x+5, y+2) you would add 5 to the x value and 2 to the y value so the answer would be L' (7,5) M' (6,4) N' (9,6)
Answer:
5 hours
Step-by-step explanation:
Normally when there is similar terms and when you have to figure out if it is factorable or prime you must first begin factoring it and if it does not work it is prime.
Hope this helps, ask me if you have any questions.
Answer:
166.32
Step-by-step explanation:
brainliest please
