Answer:
The equation in the slope-intercept form is:
Step-by-step explanation:
Given the equation
We know that the slope-intercept form of a line equation is
where
Writing the equation in slope-intercept form
-2(3x+5y)=10
-6x -10y = 10
Add 6x to both sides
-6x -10y + 6x = 10 + 6x
-10y = 10 + 6x
Divide both sides by -10
-10y / -10 = (10 + 6x) / -10
y = -3/5x - 1
Thus, the equation in the slope-intercept form is:
<em>See</em><em> </em><em>above</em><em> </em><em>information</em>
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The first thing you should know is that you need three points to be able to graph a second degree equation.
You can create a table and plot several points to obtain the parabola
In this case we will use a computational tool called wolfram alpha
Answer:
See attached image.
The graph is shown for two different intervals of the domain.
You roll a die with the sample space S = {1, 2, 3, 4, 5, 6}. You define A as {1 ,4, 6}, B as {1, 3, 4, 5, 6}, C as {1, 5}, and D
Lilit [14]
Answer:
Step-by-step explanation:
Recall that two events A,B are called mutually exclusive if and only if 
(their intersection is empty). They are exhaustive if they are mutually exclusive and their union is the sample space.
Based on this
a) Note that 
, so they are not mutually exclusive nor exhaustive.
b) 
so they are not mutually exclusive nor exhaustive.
c) 
, so they are mutually exclusive. Note that 
. Then they are exhaustive.
d) 
, so they are not mutually exclusive nor exhaustive.
