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Igoryamba
2 years ago
9

The chocolate candy below is being wrapped in a cardboard box. How many square centimeters area needed for the box?

Mathematics
1 answer:
Whitepunk [10]2 years ago
3 0

The total area of cardboard needed is equal to 121.34 square centimeters.

<h3>How many square centimeters area needed for the box?</h3>

This is equal to the surface of the given chocolate.

First, we will have two sides that are rectangles measuring 16cm by 2.6cm, so the area is:

A = 16cm*2.6cm = 41.6cm^2

Then we have another rectangular side which is the bottom one, that is a rectangle of 2.2cm by 16cm, so the are is:

A' = 2.2cm*16cm = 35.2cm^2

Finally, we have the areas of the two triangular faces, the areas of these are:

A'' = 2.2cm*3cm/2 = 1.47cm^2

Then the total area of cardboard needed is:

area = 2*A + A' + 2*A'' = 2*41.6cm^2 + 35.2cm^2 + 2* 1.47cm^2 = 121.34 cm^2

If you want to learn more about areas:

brainly.com/question/24487155

#SPJ1

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In the given series of inequalities, the inequality sign determines the final outcome.

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Answer:

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Step-by-step explanation:

Here is the equation for slope-intercept form: y=mx+b

Ok first, let's find the y intercept, which is equal to b in slope-intercept form.

To find the y intercept, we need to look at the y axis. It is the point where the line touches it. The graph shows that the line touches the y axis at -8, so that is the y intercept, (0, -8).

Now, from that point, we need to find the slope, which is equal to m in slope-intercept form.

To find the slope, start on the point that you are on, which should be the y intercept, and count how many spaces you need to go up or down, and then left or right until you get to any other point on the line. These are called the rise (change in y) and run (change in x) respectively. The slope is equal to the rise over the run, or rise/run.

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One space down on the y axis is -1, and three spaces to the right on the x axis is +3, so our slope will be -1/+3, which is -1/3.

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