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Igoryamba
2 years ago
9

The chocolate candy below is being wrapped in a cardboard box. How many square centimeters area needed for the box?

Mathematics
1 answer:
Whitepunk [10]2 years ago
3 0

The total area of cardboard needed is equal to 121.34 square centimeters.

<h3>How many square centimeters area needed for the box?</h3>

This is equal to the surface of the given chocolate.

First, we will have two sides that are rectangles measuring 16cm by 2.6cm, so the area is:

A = 16cm*2.6cm = 41.6cm^2

Then we have another rectangular side which is the bottom one, that is a rectangle of 2.2cm by 16cm, so the are is:

A' = 2.2cm*16cm = 35.2cm^2

Finally, we have the areas of the two triangular faces, the areas of these are:

A'' = 2.2cm*3cm/2 = 1.47cm^2

Then the total area of cardboard needed is:

area = 2*A + A' + 2*A'' = 2*41.6cm^2 + 35.2cm^2 + 2* 1.47cm^2 = 121.34 cm^2

If you want to learn more about areas:

brainly.com/question/24487155

#SPJ1

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Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po
jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

Step-by-step explanation:

The given equation is

x^3-21x=-20

It can be written as

x^3+0x^2-21x+20=0

Splitting the middle terms, we get

x^3-x^2+x^2-x-20x+20=0

x^2(x-1)+x(x-1)-20(x-1)=0

(x-1)(x^2+x-20)=0

Splitting the middle terms, we get

(x-1)(x^2+5x-4x-20)=0

(x-1)(x(x+5)-4(x+5))=0

(x-1)(x+5)(x-4)=0

Using zero product property, we get

x-1=0\Rightarrow x=1

x-4=0\Rightarrow x=4

x+5=0\Rightarrow x=-5

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

3 0
3 years ago
Find the inverse of the function f(x) = (x - 4) 2 - 5 if x ≥ 4.
Serggg [28]
Same here, we do a quick switcharoo on the variables first,

\bf \stackrel{f(x)}{y}=(x-4)^2-5\qquad inverse\implies \boxed{x}=\left( \boxed{y}-4 \right)^2-5&#10;\\\\\\&#10;x+5=(y-4)^2\implies \pm\sqrt{x+5}=y-4\implies \pm\sqrt{x+5}+4=y
6 0
3 years ago
Orlando invests $1000 at 6% annual interest compounded daily and Bernadette invests $1000 at 7%
Montano1993 [528]

Answer:

6 Years

Step-by-step explanation:

Orlando invests $1000 at 6% annual interest compounded daily.

Orlando's investment = A=1000(1+\frac{0.06}{365})^{(365\times t)}

Bernadette invests $1000 at 7% simple interest.

Bernadette's investment = A = 1000(1+0.07×t)

By trail and error method we will use t = 5

Bernadette's investment will be after 5 years

1000(1 + 0.07 × 5)

= 1000(1 + 0.35)

= 1000 × 1.35

= $1350

Orlando's investment after 5 years

A=1000(1+\frac{0.06}{365})^{(365\times 5)}

   = 1000(1+0.000164)^{1825}

  = 1000(1.000164)^{1825}

  = 1000(1.349826)

  = 1349.825527 ≈ $1349.83

After 5 years Orlando's investment will not be more than Bernadette's.

Therefore, when we use t = 6

After 6 years Orlando's investment will be = $1433.29

and Bernadette's investment will be = $1420

So, after 6 whole years Orlando's investment will be worth more than Bernadette's investment.

8 0
3 years ago
As part of a study of the association between smoking and risk of squamous cell carcinoma, a logistic regression model was estim
AlekseyPX

Answer:

0.44

Step-by-step explanation:

Given the estimated logistic regression model on risk of having squamous cell carcinoma

-4.84 + 4.6*(SMOKER)

SMOKER = 0 (non-smoker) ; 1 (SMOKER)

What is the predicted probability of a smoker having squamous cell carcinoma?

exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))

SMOKER = 1

exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)

exp^(-0.24) / (1 + exp^(-0.24))

0.7866278 / 1.7866278

= 0.4402863

= 0.44

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