Solve for the first variable in one of the equations, then substitute the result into the other equation.
Y
=
2
y
/3
−
3
x
=
−
y
/3
+
7
Hope this helped!
Answer: Option D
Step-by-step explanation:
By definition if we have a function F (x) and perform a transformation of the form

Then it is true that:
If c is negative the graph of G(x) will be equal to the graph of F(x) displaced horizontally c units to the right
If c is positive, the graph of G(x) will be equal to the graph of F(x) displaced horizontally c units to the left.
Note that in this case the transformation is:

Then
and 
Therefore the graph of G(x) will be equal to the graph of F(x) displaced horizontally <em>9 units to the left</em>
The answer is the option D.
Answer:
Empirical probability
Step-by-step explanation:
Empirical probability is data collected from experiment and real-life situation.
The "empirical probability" of an outcome is obtained by dividing the frequency of occurrence of an event by the number of trails of the experiment.

- <u>Therefore, the correct answer is empirical probability.</u>
I hope this helps you! Let me know if my answer is wrong or not.
Answer:
70/5985
Step-by-step explanation:
We know that a quadrilateral needs to have four vertices (or points on the circle). There are always two ways to link the cross — horizontally or vertically. Using my limited knowledge of combinations, we know that choosing four points out of seven equals 35. Multiplying the two ways to connect those lines (again, horizontally and vertically) makes 35*2 = 70 "bow-tie quadrilaterals" that can be formed on the circle using four points. There are 5985 ways four chords can be chosen out of twenty-five chords because C(25,4) equals 5985, so the probability is 70/5985... and then we just need to simplify that fraction.
The sample % of these two populations would be 100/size (of student body at each school) x 100 so this would compare the two student bodies preferences for the particular type of candy bar. However, the actual % of the whole student body at each school would be a factor also. If the high school only had 200 students then this would be 50% representative but if the middle school had say 500 students this would only be 20% representative so this would have to be taken into account too. It might be more representative to have the same % of the student bodies respectively for the sample.