PLEASE HELP DUE SOON, ILL GIVE BRAINLIEST TO WHOEVER EXPLAINS THE ANSWER GOOD

Mathematics

1 answer:

Cloud [144]3 years ago

4 0

Answer:

answer is d...... ... ..

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The sum of the first n terms of an arithmetic sequence is n/2(4n + 20).

lesantik [10]

Answer:

(a).

$S_{n} = \frac{n}{2} (4n + 20) \\ \\S _{n - 1} = \frac{(n - 1)}{2} (4n - 4 + 20) \\ \\ S _{n - 1} = \frac{(n - 1)}{2} (4n + 16) \\ \\S _{n - 1} = \frac{(n - 1)(4n + 16)}{2} \\ \\ { \boxed{S _{n - 1} = {2 {n}^{2} + 6n - 8}}} \\$

(b).

from general equation:

$S _{n - 1} = \frac{(n - 1)}{2} (4n + 16)$

first term is 4n

common difference:

$16 = \{(n - 1) - 1 \}d \\ 16 = (n - 2)d \\ d = \frac{16}{n - 2}$

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PSYCHO15rus [73]

I think it is x > 5 because if you combine like terms you would get 2x-4>6 then you add 4 To 6 which is 10 then you do 10÷2 which is 5

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jeyben [28]

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im not sure if this is correct but i think it is :)