9 . 27 21 Solve for 3

I need this fast!........................

Schach [20]

Answer: $(2,2)$

Step-by-step explanation:

1. Substitute $y=0$ into first equation and solve for "x" in order to find the x-intercept of the first line:

$0=-\frac{1}{2}x+3\\\\-3=-\frac{1}{2}x\\\\(-3)(-2)=x\\\\x=6$

2. Substitute $x=0$ into the first equation and solve for "y" in order to find the y-intercept of the first line:

$y=-\frac{1}{2}(0)+3\\\\y=3$

Knowing that first line passes through the points $(6,0)$ and $(0,3)$ , you can graph it.

3. Substitute $y=0$ into second equation and solve for "x" in order to find the x-intercept:

$0=2x-2\\\\2=2x\\\\x=1$

4. Substitute $x=0$ into the second equation and solve for "y" in order to find the y-intercept of the second line:

$y=2(0)-2\\\\y=-2$

Knowing that second line passes through the points $(1,0)$ and $(0,-2)$ , you can graph it.

The solution of the system of equations is the point of intersection between the lines. Therefore, the solution of this system is:

$(2,2)$

7 0

2 years ago

Katalin drove 300 miles on her vacation. She drove an average of 1.9 times faster on the second 150 miles of her trip than she d

viktelen [127]

300=x+1.9x
I got this by dividing the problem into two parts x[the speed of the first half] plus 1.9x [the speed of the second half increased by 1.9] both of those together should give you 300.
I went further and solved this...If you placed 103.5 into this problem for x you should get 300.15!

8 0

2 years ago

A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of

cestrela7 [59]

The amount of gas consumed by first and second car were 20 gallons and 15 gallons respectively.

Explanation

Suppose, $x$ gallons of gas were consumed by the first car.

As the total gas consumption in one week is 35 gallons, so the amount of gas consumed by second car will be: $(35-x)$ gallons.

The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 15 miles per gallon of gas.

So, the distance traveled by the first car in $x$ gallons of gas $=35x$ miles and the distance traveled by the second car in $(35-x)$ gallons of gas $=15(35-x)$ miles.