Ask question

Ask question

All categories

3 years ago

9

Mr. Brown’s bank account is overdrawn $110.55 and he deposits $18 a week. His wife has a separate account and her account is als

o overdrawn $63.12 and she deposits $22.50 a week. How many weeks will it be before Mr. Brown’s wife has more in her account than her husband?

1 answer:

Basile [38]3 years ago

7 0

Answer:

y=mx+b sdi c xc xx cx cx cxc xc 87

Step-by-step explanation:

You might be interested in

When u are doing math and u have a question with pi in it don't u use "3.14" or do u use "3.141" or is it "3.14159?

Tju [1.3M]

Usually, I use 3.14.

7 0

4 years ago

Read 2 more answers

Do the sides make a unique triangle or no?

gregori [183]

Answer:

No

Step-by-step explanation:

8 0

3 years ago

Simplify:<br> 3x3 (4x4 + 3y)

luda_lava [24]

Answer:

144+27y

Step-by-step explanation:

3x3(4x4+3y)

9(16+3y)

144+27y

5 0

3 years ago

To which graph does the point (−1, 3) belong? y ≥ 2x + 6 y ≥ 3x − 1 y ≥ −x + 3 y ≥ −2x + 5

Anna35 [415]

Well first find the slope of the point
y=mx+b y=-1x+3
slope = -1
then put the problem in point slope form y - y1 = m (x-x1)
y + 3 = -1 (x+1) then solve for y=mx+b again
so y> 2x + 6 is the answer

4 0

3 years ago

Read 2 more answers

Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (

Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that $I=\int_0^3 x^3-4x dx=9/4$ . We use the properties of integrals to write the new integrals in terms of I.

A) $\int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2$ . We have used that ∫cf dx=c∫f dx.

B) $\int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4$ . Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

4 0

3 years ago