Answer:
The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the reading speed of a sixth-grader whose reading speed is at the 90th percentile
This is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.




The reading speed of a sixth-grader whose reading speed is at the 90th percentile is 155.72 words per minute.
Answer:
7
Step-by-step explanation:
7x + 68 = 2x + 103
Subtract 2x from each side
5x + 68 = 103
Subtract 68 from each side
5x = 35
divide 5 from 35 and you get X = 7
Answer:
the correct answer is x = 2
37.5
9/24=0.375
Move the decimal two places and you get 37.5%
Answer:
See answer below
Step-by-step explanation:
For the first expression
3 x (x - 2) + 2 = 3 x^2 - 6 x + 2
evaluated at x= 4 we get: 26
and for x = 5 we get 47.
For the second expression
2 x^2 + 3 x - 18
we get the exact same values when doing the evaluation at these two points.
Based on those results, one may think the expressions may be equivalent, but they are not equivalent. Because at any other x-value, their results are different. See for example that for x = 0 the first one gives "2" while the second one gives -18.