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3 years ago

Please help me

Mathematics

1 answer:

puteri [66]3 years ago

3 0

I will rounded up too 45 right answer

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Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12 a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0

3 years ago

Graph the system of linear equations. y = x + 5 and y = 2x + 2.

Oxana [17]

Graph using y=mx+b. The point of intersection is (3,8)

4 0

3 years ago

30 points if I had 125 quarter how much money I would have

inna [77]

Answer:

$31.25

Step-by-step explanation:

125 divided by 4 = 31.25

$31.25

4 0

2 years ago

Read 2 more answers

I need help on my homework

soldi70 [24.7K]

Answer:

$\displaystyle m\angle AED=32.5^\circ$

Step-by-step explanation:

Angles in a Circle

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

Segments AE and DE are secants of the given circle. They form an exterior angle called AED.

The measure of an exterior angle is equal to half the difference of the measure of their intercepted arcs.

Intercepted arcs in the given circle are AD=113° and BC=48°. The exterior angle is:

$\displaystyle m\angle AED=\frac{AD-BC}{2}$

$\displaystyle m\angle AED=\frac{113^\circ-48^\circ}{2}=\frac{65^\circ}{2}$

$\displaystyle m\angle AED=32.5^\circ$

8 0

3 years ago

Is the following relation a function? A. Yes B. No

SVETLANKA909090 [29]

Answer:

B. No

Step-by-step explanation:

In order for the relation to be a function, each X value must source exactly one arrow. The value -1 maps to two different values (2, -1), so the relation is NOT A FUNCTION.

3 0

2 years ago