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3 years ago

a computer screen has a length of 16 inches and a width of 12 inch what is the area of the computer screen

Mathematics

1 answer:

pashok25 [27]3 years ago

8 0

Answer: The area of the computer screen is 192

Step-by-step explanation:

Legnth times width so 16 x 12 which equals 192

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Henry was buying meals for his family. He bought 3 meals that included a chicken, corn, and a drink and spent a total of $20.25.

riadik2000 [5.3K]

Answer:

The price of each meal cost before tax is $ 6.367

Step-by-step explanation:

Given as :

The total price of three meals = $ 20.25

The sales tax included in the total price = 6 %

So, Let the cost of meal before sales tax = x

Or, x + 6 % of x = $ 20.25

or, x + 0.06 x = $ 20.25

Or, 1.06 x = $ 20.25

∴ x = $\frac{20.25}{1.06}$

I.e x = $ 19.10

Or, price of three meals before tax = $ 19.10

so, The price of each meal = $\frac{19.10}{3}$ = $ 6.367

Hence The price of each meal cost before tax is $ 6.367 answer

5 0

3 years ago

following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in

valina [46]

Note: As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

Daily expenditure on milk (in Rs) Number of households

0-30 5

30-60 6

60-90 9

90-120 6

120-150 4

Here the maximum frequency is 9.

So, modal class is 60-90.

As the formula to calculate the mode:

$Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )$

Here, the maximum

$l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30$

$l=$ is the lower limit of the class

$f_{1} =$ is the frequency of the modal class

$f_{0} =$ is the frequency of the previous modal class

$f_{2} =$ is the frequency of the next previous modal class

$l=$ is the class size

So,

$Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )$

$Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )$

$Mode = 60 + \frac{(30)(3)}{6}$

$Mode = 60 + 15=75$

∴ The mode of the data = 75

Keywords: mode, frequency distribution

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The sum of two numbers,x and y,is more than8.When you double x and add it to y,the sum is less than 14.

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3 years ago

a computer screen has a length of 16 inches and a width of 12 inch what is the area of the computer screen ​

a computer screen has a length of 16 inches and a width of 12 inch what is the area of the computer screen