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3 years ago

(4x – 3) + (–x + 5) =

Mathematics

2 answers:

tekilochka [14]3 years ago

7 0

Answer:

3x+2

Step-by-step explanation:

Volgvan3 years ago

5 0

Answer:

x=-0.4

Step-by-step explanation:

(4x-3)+(-x+5)=0

Distribute the positive

4x-3+x+5=0

Combine like terms

5x+2=0

5x=-2

x=-0.4

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Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

4 0

3 years ago

Someone please answer this, ill give you brainliest and your getting 100 points.

andrew11 [14]

Answer:

Step-by-step explanation:

First sequence : 10,9.5,9,8.5,...

Let's see the difference between 2 numbers :
10 - 9.5 = 0.5
9.5 - 9 = 0.5
9 - 8.5 - 0.5

So on and so on. So, the common difference between these numbers are 0.5

Next sequence : 200,100,50,25, ...

We see, to get from one number to another, we divide it by 2 / multiply it by 1/2.

200 x 1/2 = 100
100 x 1/2 = 50
50 x 1/2 = 25

So on and so on. So, the common ratio of these numbers are 1/2.

6 0

2 years ago

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77julia77 [94]

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5 0

3 years ago

I need help with this math problem

dimaraw [331]

Choice J both prices are per a unit

7 0

3 years ago

Tim,Griff and Kay baked chocolate for Kay s birthday party.Tim baked 3 times as many as Kay.Griff baked half as many as Tim.Alto

lianna [129]

Answer: 48

------------------------------------------------------------------------------
Define the number of cakes they baked in term of x
------------------------------------------------------------------------------
Let the number of cakes Kay baked be x

Kay = x
Tim = 3x   ← Tim baked 3 times as many as Kay
Griff = 1.5x   ← Griff baked 1/2 as many as Tim

------------------------------------------------------------------------------
Construct the equation and solve for x
------------------------------------------------------------------------------
The total number of cakes baked was 88.

x + 3x + 1.5x = 88   ← Combine like terms
5.5 x = 88 ← Divide by 5.5
÷5.5   ÷5.5
x = 16

------------------------------------------------------------------------------
Find the number of cakes each baked
------------------------------------------------------------------------------
Kay = x = 16
TIm = 3x = 16 x 3 = 48
Griff = 1.5x = 1.5(16) = 24

------------------------------------------------------------------------------
Answer: Tim baked 48 cakes.
------------------------------------------------------------------------------

3 0

4 years ago