Answer:
Step-by-step explanation:
The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.
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<h3>Given relation</h3>
Let x represent the width of the shed. Then the length is (2x+3), and the area is ...
A = LW
20 = (2x+3)(x) . . . . . area of the shed
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<h3>Solution</h3>
Completing the square gives ...
2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides
2(x +0.75)² = 21.125 . . . . . . . write as a square
x +0.75 = √10.5625 . . . . . divide by 2, take the square root
x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution
The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.
22(1 + 4 + 9 + 16 +251 + 4 + 9 + 16 + 25 + 3636)
= 87362 units^2
Answer:
-13
Step-by-step explanation:
Answer:
-2
Step-by-step explanation:
If we have an equation of the form y = mx +b then the y-intercept is b.
So now here we have y =-x - 2. Therefore b = -2 and we conclude the y-intercept is -2.
Answer:
x = 3
Step-by-step explanation:
Given the 2 equations
x + y = 3 → (1)
2x - y = 6 → (2)
Adding the 2 equations term by term eliminates the y- term, that is
3x = 9 ( divide both sides by 3 )
x = 3
