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guapka [62]
3 years ago
9

WILL GIVE BRAINLIEST. If x+y=3 and 3x+5y=13, then x-y is equal to?

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

(1,2)

y=2

x=1

Step-by-step explanation:

x+y=3

3x+5y=13

solve the equation

x=3-y

3x+5y=13

substitute the value of x into an equation

3(3-y)+5y=13

distribute

9-3y+5y=13

add -3y to 5y

9+2y=13

subtract 9 from both sides

2y=4

divide both sides by 2

y=2

substitute the value of y into an equation

x=3-2

subtract 3 to 2

x=1

--------

(1,2)

--------

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Han has 4 dimes. What percent of a dollar does Han have?
Mama L [17]

Answer:

40%

Step-by-step explanation:

4 dimes = 40 cents

1 dollar = 100 cents

40\frac{40}{100} = 40%

7 0
3 years ago
Prism A has a volume of 60 cubic units and a height of 12 units. Prism B has the same base area and height but a length of 15 un
stepladder [879]

Answer:

As both prism have the same base area and height there volumes are the same.

Step-by-step explanation:

Volume of the prism is given by

Volume of Prism A= base area* height

60 cubic units= base area* 12

base area= 60/12= 5 units

Volume of Prism B= base area* height

                              = 5 units*12 units

                             = 60 cubic units

As both prism have the same base area and height there volumes are the same.

The length of the longer side is the length of the triangle itself.

For example the length of longer side of prism A maybe 10 units but width may be 1/2 units

and

the length of longer side of prism B maybe 15 units but width may be 1/3 units

the total base area remains the same.

5 0
3 years ago
Read 2 more answers
Determine the mode for the following set of tests score 63,70,75,80,85,85.85,92,92,95,99
Mariulka [41]

The mode is 85, because it is the most occurring in the data set.

hope that helps :)

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3 years ago
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I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5
Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}

Similarly, using
\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
we derive
\frac{d}{dx}(-\sqrt{3-3x^2})
=\frac{3x}{\sqrt{3-3x^2}}

Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
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3 years ago
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I think when you put the numbers orderwise

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2 years ago
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