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balu736 [363]
3 years ago
14

Uh please answer correctly I’ll mark you brainlist after I see if it’s correct!

Mathematics
2 answers:
zepelin [54]3 years ago
6 0

Answer:

The equation for the volume of a rectangular prism is V=whl or width x height x length. The width is 7/2, the height is 7/5, and the length is 5. Multiply all of these numbers to get 49/2 or 24.5.

xxMikexx [17]3 years ago
5 0

Answer:

24.5 cm cubed

(3.5 (7/2) times 1.4 (7/5) times 5)

Step-by-step explanation:

7/2cm  multiplied by 7/5cm multiplied by 5cm

(3.5 times 1.4 times 5 = 24.5)

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Evaluate 4x^2 y^-3 for x=3 and y=-2
Doss [256]

Answer:

36   and -1/8

Step-by-step explanation:

x^2 = 3^2 = 9 * 4 = 36

y^-3 = (-2)^-3 = -1/8

6 0
3 years ago
Read 2 more answers
The sales tax in mike's state is 6%. mike bought a jetta having a sales tax of $820. what was the cost of the vehicle? round to
Tems11 [23]
$13, 666.67
because you would do 820 divided by 0.06 and you get 13,666.6667 which you round to 13,666.67
6 0
3 years ago
What is the value of x
irga5000 [103]

Answer:

X=24

Step-by-step explanation:

1. (4x + 11) + (3x + 1) = 180 (Combine like terms)

2. 7x + 12 = 180 (Subtract 12 from both sides)

3. 7x = 168 (Divide both sides by 7)

4. x = 24

3 0
3 years ago
A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.
pav-90 [236]

Answer:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.25 represent the population standard deviation

n represent the sample size  

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

3 0
3 years ago
2 math questions. Please show your work if you can, I struggle with this, Thanks !!<br> 20pts
castortr0y [4]

Step-by-step explanation:

To find the solution, Tanisha can graph each side of the equation as its own function:

y₁ = log₃(5x)

y₂ = log₅(2x + 8)

The solution is where the two curves cross.  From the graph, that happens at x ≈ 0.957.

desmos.com/calculator/lkukjhn3g2

5 0
3 years ago
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