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Kruka [31]
3 years ago
13

Divide a 6 and 3/4 inch line into three parts so that each part is 1/4 inch shorter than the one before it.

Mathematics
1 answer:
Stells [14]3 years ago
4 0

Answer:

Hey there!

x+x+1/4+x+2/4

3x+0.75=6.75

3x=6

x=2

The lines are 2, 2 1/4, and 2 2/4.

Let me know if this helps :)

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PLEASE HELP
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the three cubes shown weigh 12 ounces how many pounds would 24 cubes weigh A. 4.5 lb B. 6lb C. 18lb D. 72lb
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7 0
3 years ago
The area of a room is 600 square feet. The length is (x + 5) feet and the width is (x + 4) feet. Find the dimensions of the room
tangare [24]
I'm going to assume that the room is a rectangle.

The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle. 

You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:
A = lw\\
600 = (x+5)(x+4)\\
600 =  x^{2} + 9x + 20


Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:
600 = x^{2} + 9x + 20\\
x^{2} + 9x - 580 = 0\\
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x + 29 = 0, \:\: x - 20 = 0\\
x = -29, x = 20

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.

The dimensions of your room are 25ft (length) by 24ft (width).
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