Josh practices gymnastics each day

What is the relation between 1 and 2?

Tju [1.3M]

Answer:

Supplementary and Linear Pair

Step-by-step explanation:

The angles 1 and 2 form 180 degrees. That is the definition of a Supplementary Angle and Linear Pair.

4 0

4 years ago

How many different 7-place license plates are possible if the first 2 places are for letters and the other 5 for numbers probabi

yarga [219]

The total number of possible 7-place license plates are 67600000.

Given: A 7-plate license plate. 2 places are for letters and 5 places are for numbers. To find how many different 7-plate license plates are possible

Let's solve the given problem:

The license plate has 7 places. 2 places are for letters and the remaining 5 places are for numbers.

Combination of letters: As there are no restrictions given in the question, so the first letter can be any alphabet out of the 26 alphabets (A, B, C, D, ......... Z). So the first place for the letter can be filled in ²⁶C₁ ways that are 26 ways. Also for the second place, as the letters can repeat so it can be filled in ²⁶C₁ ways too which are 26 ways. Therefore, the possible ways in which the place for two letters can be filled is 26 × 26 ways = 676 ways.
Combination of numbers: As there are no restrictions given in the question so the first number can be any of the numbers out of the 10 numbers (10, 1, 2, 3, ....... 9). So the first number can be filled in ¹⁰C₁ = 10 ways. Similarly, as the numbers can repeat so the 2nd, 3rd, 4th and 5th numbers can be filled in ¹⁰C₁ ways that all the other places can be filled in 10 ways each. Therefore the total number of ways in which the place for 5 numbers can be filled is 10 × 10 × 10 × 10 × 10 ways = 100000 ways.

Therefore, the total number of ways in which the 7-place license plate can fill are: Total possible ways in which the two letters can be filled × Total possible ways in which the 5 number places can be filled

= 676 × 100000

= 67600000 ways

Hence the total number of possible 7-place license plates are 67600000.

Know more about "permutations and combinations" here: brainly.com/question/13387529

#SPJ6

3 0

2 years ago

Which expression is equivalent to 4 √10 ? (૧/x 0 x ² 022 ○ +³² (+ √/x) 0 +5

zimovet [89]

The answer should be 022

6 0

2 years ago

Find the sum \[\sum_{k = 1}^{2004} \frac{1}{1 + \tan^2 (\frac{k \pi}{2 \cdot 2005})}.\]

vampirchik [111]

Answer:1002

Step-by-step explanation:

$\Rightarrow \sum_{k=1}^{2004}\left ( \frac{1}{1+\tan ^2\left ( \frac{k\pi }{2\cdot 2005}\right )}\right )$

and $1+\tan ^2\theta =\sec^2\theta$

and $\cos \theta =\frac{1}{\sec \theta }$

$\Rightarrow \sum_{k=1}^{2004}\left ( \cos^2\frac{k\pi }{2\cdot 2005}\right )$

as $\cos ^2\theta =\cos ^2(\pi -\theta )$

Applying this we get

$\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]$

every $\theta$ there exist $\pi -\theta$

such that $\sin^2\theta +\cos^2\theta =1$

therefore

$\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]=1002$