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3 years ago

Babatunde has a mass of 78kg. What would Babatunde weigh on the Moon? (The gravitational field strength on the Moon is 1.6N/kg.)

Mathematics

1 answer:

Rina8888 [55]3 years ago

5 0

Answer:

Babatunde weigh on the Moon would be 124.8 N

Step-by-step explanation:

* The wight of an object on the earth is mg , where m is the the

mass of the object in kg and g is the acceleration of gravity which

is 9.8 m/s²

* The mass of an object on earth is the same as the mass of the

same object on the moon but the weight of the object on the

earth is different from the weight of the same object on the

moon because the gravity on the earth different from on the moon

* The wight on the moon is mg , where m is the the mass of the

object in kg and g is gravitational field strength on the Moon

which is 1.6 N/kg

∵ Babatunde has a mass of 78 kg

∵ The mass on the moon = the mass on the earth

∵ On the moon the gravitational field strength is 1.6N/kg

∵ Weight = mg

∴ Babatunde weigh = 78 × 1.6 = 124.8 N

* Babatunde weigh on the Moon would be 124.8 N

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Habiendose organizado un bingo se ha recaudado $1900. Por la entrada de hombres $15 y mujeres $10 y se ha reportado una asistenc

aev [14]

Answer:

The number of men was $80$

The number of women was $70$

Step-by-step explanation:

The question in English is

Having organized a bingo has raised $1900. For the entrance of men $15 and women $10 and an attendance of 150 people has been reported. Determine the number of men and the number of women who participated in the bingo.

Let

x----> the number of men

y----> the number of women

we know that

$x+y=150$

$x=150-y$ -----> equation A

$15x+10y=1,900$ -----> equation B

substitute equation A in equation B and solve for y

$15(150-y)+10y=1,900$

$2,250-15y+10y=1,900$

$15y-10y=2,250-1,900$

$5y=350$

$y=70$

Find the value of x

$x=150-70=80$

therefore

The number of men was $80$

The number of women was $70$

3 0

3 years ago

Please help me! I'm terrible at math

Hatshy [7]

Answer:

(3.) x = 45

Step-by-step explanation:

Because the lines are parallel and cut by the same line, the angles within are equal as well.

Which means that...

Angle GE = Angle EFD

Therefore (2x-30) = (x + 15)

2x - 30 = x + 15

+30 +30 (add 30 to both sides to get rid of the -30)

2x = x + 45

-x -x (subtract x from both sides to get rid of the single positive x)

x = 45

3 0

3 years ago

Solve 8x - 5y = 14 for y.

emmasim [6.3K]

9 is y is the answer

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3 years ago

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What is 4/5 ( 4 over 5) times 3?

sveta [45]

Maybe the answer would be 12/5

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3 years ago

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The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that

Mnenie [13.5K]

Answer:

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

6% of the city's population moves to the suburbs (and 94% stays in the city).
2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

$A= \left \begin{array}{cc} \\ C \\S \end{array} \right\left[ \begin{array}{cc} C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]$

The population in the year 2000 (initial state) is given as:

$\left[ \begin{array}{cc} C&S\\ 500,000&700,000 \end{array} \right]$

Therefore, the population of the city and the suburb in 2002 (two years after) is:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2$

$A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]$

Therefore:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]$

Therefore, the population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

6 0

3 years ago