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jonny [76]
3 years ago
13

A function, f left parenthesis x right parenthesis comma models the depth of water in a wading pool that is filling at a rate of

11 gallons per minute. Which of these describes why f left parenthesis x right parenthesis can be considered a linear function? I. For every 1 minute interval, the depth of water in the wading pool increases by the same amount. II. The function grows by equal factors every minute. III. The slope of the function is constant.
Mathematics
1 answer:
Allisa [31]3 years ago
6 0

Answer:

quiz let or brainy helps me just look up the chapter question and you will get the answer

Step-by-step explanation:

hope this helps

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Answer:

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HELP DUE IN 10 MINS!<br><br> Attached is the Question.
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Answer:

  • ∠N ≅ ∠J - given
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<u>Postulate</u>: ASA

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3 years ago
What are the next three terms of the sequence below?
vichka [17]

<u>Answer:</u>

  • 64, 256, 1024 (D)

<u>Step-by-step </u><u>Explanation</u><u>:</u>

The sequence is following some rule. And the rule is: Multiplying the term with 4 to get the next term. Like:

  • 1 × 4 = 4
  • 4 \times 4 = 16

Similarly, the next terms are:

  • 16 \times 4 = 64
  • 64 \times 4 = 256
  • 256 \times 4 = 1024

The terms are <u>6</u><u>4</u><u>,</u><u> </u><u>2</u><u>5</u><u>6</u><u>,</u><u> </u><u>1</u><u>0</u><u>2</u><u>4</u> which matches with Option D. And that's the correct answer

4 0
2 years ago
Read 2 more answers
What is seven squared?
Goryan [66]
Ur answer is going to be 49
7 0
3 years ago
What equation best models this data?(use y to represent the population of rabbits and t to represent the year, assuming that 201
liraira [26]

If we see the data closely, a pattern emerges. The pattern is that the ratio of the population of every consecutive year to the present year is 1.6

Let us check it using a couple of examples.

The rabbit population in the year 2010 is 50. The population increases to 80 the next year (2011). Now, \frac{80}{50}=1.6

Likewise, the rabbit population in the year 2011 is 80. The population increases to 128 the next year (2012). Again, \frac{128}{80}=1.6

We can verify the same ratio with all the data provided.

Thus, we know that the population in any given year is 1.6 times the population of the previous year. This is a classic case of a compounding problem. We know that the formula for compounding is as:

F=P\times r^n

Where F is the future value of the rabbit population in any given year

P is the rabbit population in the year "0" (that is the starting year 2010) and that is 50 in this question. (please note that there is just one starting year).

r is the ratio multiple with which the rabbit population increases each consecutive year.

n is the nth year from the start.

Let us take an example for the better understanding of the working of this formula.

Let us take the year 2014. This is the 4th year

So, the rabbit population in 2014 should be:

F_{2014} =50\times(1.6)^4\approx328

This is exactly what we get from the table too.

Thus, F=P\times r^n aptly represents the formula that dictates the rabbit population in the present question.

4 0
3 years ago
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