Answer:
a) 2.5 km
b) 1836 m ≈ 1.8 km (rounded)
Step-by-step explanation:
a) just add the two distances of the vertical and horizontal road. 900m + 1600m = 2500m = 2.5 km
b) Apply Pythagoras (a²+b²=c², where a and b are the vertical and horizontal roads, and c is the diagonal road).
c = √(1600²+900²) ≈ 1836m (rounded)
Given:
3n + 5
n = 1 ; 3(1) + 5 = 3 + 5 = 8
n = 2 ; 3(2) + 5 = 6 + 5 = 11
n = 3 ; 3(3) + 5 = 9 + 5 = 14
n = 4 ; 3(4) + 5 = 12 + 5 = 17
The first four terms of the sequence are: 8, 11, 14, 17. Second option.
<span>Amplitude: 3; period: pi/2; midline: y = 2</span>
Answer:
-3x^3+74x-5
Step-by-step explanation:
(x+5)(-3x^2+15x-1)
-3x^3+15x^2-x-15x^2+75x-5
-3x^3+15x^2-15x^2+75x-x-5
-3x^3+74x-5
