A is the answer hope i helped
D) #recombinant=116+601+4+2+113+625=1462
#nonrecombinant=2538+2708=5246
RF=R/(N+R)=1462/6708=0.2
E) I=1-Q
I-interference
Q-coefficient of coincidence
Q=O2Xo/E2xo(2xo-double crossovers)
O2xo=6
P=(distance from C1 to Sh/100)*(distance from Sh to Wx/100)
=(3.38/100)*(18.28/100)=0.006
E2xo=0.006*6708=40.248
Q=6/40.248=0.15
I=1-0.15=0.85
We'll make the alleles: Cc.
C is a healthy parent, and c is the cystic fibrosis (recessive).
If you make a punnett square and the parents are both Cc (healthy), then you would get CC, Cc, Cc, and cc. That cc is a 25% chance that the offspring will have that, which means there is a 25% chance the child will have cystic fibrosis.
Two healthy parents can have a child with cystic fibrosis if both the parents have the dominant allele and recessive allele, if both the parents have heterozygous alleles.
The compounds present in plants that, in a way, assist in the absorption of light during the process of photosynthesis, are accessory pigments. As their name suggests, they act as helpers or assist chlorophyll in absorption of light. These may be chlorophyll variants or other classes.
