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blsea [12.9K]
3 years ago
9

Sunlight-Rose-Honeybee-Skunk-Eagle

Biology
2 answers:
postnew [5]3 years ago
4 0

The rose population would decrease because the bees would need more food. Since the skunk has more food, it would increase and the eagle population would probably increase too because of more access to skunks. The eagle interpretation may be true unless the eagle is perceived as a scavenger. Then the population would most likely stay the same. The sun would stay the same because it is an abiotic factor in an ecosystem. your welcome fam

sineoko [7]3 years ago
4 0

Sunlight is the same (obvs) then roses decrease because there are more honeybees to eat them. Skunks would probably increase bc there are lots more honeybees to eat but then honeybees decrease probably. Eagles increase cos skunks increased after honeybees increased. Basically sunlight stays same, roses dercrease and the rest increase.

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Following the Hardy-Weinberg equilibrium theory, the frequency of the heter0zyg0us genotype is 2pq. In the exposed example, 2pq = 0.48.

<h3>Hardy-Winberg equilibrium</h3>

The Hardy-Weinberg equilibrium theory states that the allelic frequencies in a locus are represented as p and q.

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If a population is in H-W equilibrium, it gets the same allelic and genotypic frequencies generation after generation.

The addition of the allelic frequencies equals 1  ⇒ p + q = 1.

The sum of genotypic frequencies equals 1 ⇒ p² + 2pq + q² = 1

If the allele A has a frequency of 0.6, and the allele B has a frequency of 0.4, then the frequency of the heter0zyg0us genotype is

2pq = 2 x 0.6 x 0.4 =<u> 0.48</u>

You can learn more about the Hardy-Weinberg equilibrium at

brainly.com/question/3406634

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