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2 years ago

15

Verify -(-x) = x for: a)

\frac{5}{9}" align="absmiddle" class="latex-formula">
b) $\frac{-3}{8}$

1 answer:

Mila [183]2 years ago

5 0

It a because negative times a negative is a positive

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Find the LCM of 12, 16, and 20

laila [671]

The LCM of 12,16, and 20 would be 240

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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

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2 years ago

Help me answering this question

tatuchka [14]

Answer:

D

Step-by-step explanation:

when we perform each of these transformations, the only one that does <u>NOT</u> make shape F congruent (the same position, orientation and size) with shape G, for it reflects over and axis making it mirror to G, but is then ROTATED 90 degrees into shape G's sector, rotating the shape 90 degrees as well

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2 years ago

How do you do this?

tresset_1 [31]

Basically you just count how many there is of each.
So the answers would be:
Pentagon = 1
Triangle = 7
Moon = 1
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2 years ago

Does 2/7 =11/37 because idk

Bad White [126]

Answer:

no. i do not think so.

Step-by-step explanation:

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