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MrRa [10]
3 years ago
6

Me Pekzer has a problem he has become obsessed with TickTock's he makes them all the time now when he started counting he had ma

de 544 different TickTock's he did some calculations and determined the number of TickTock's he made was growing by 11% each week write an equation to represent this situation .
Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0

Answer:

544w + 11%

Step-by-step explanation:

544 is the number he started with, so if he increases 11% by w (the amount of weeks) then you will get your anwser based on the number of weeks he increases

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What is the binomial expansion of (x + 2y)7?
borishaifa [10]
<h2>Thus, the required "option 4)"  is correct.</h2>

Step-by-step explanation:

We find,

(x+2y)^7

To find, the binomial expansion of of (x+2y)^7 = ?

We know that,

(x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n

∴ (x+2y)^7

Here, n = 7, x = x and y = 2y

(x+2y)^7= ^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

∴ The binomial expansion of of (x+2y)^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

Thus, the required "option 4)"  is correct.

7 0
3 years ago
The points (3,-2) and (2, 1) are both solutions to which inequality?
KIM [24]

(3, -2) and (2, 1) are solutions to the inequality y <= 3/2x - 1

<h3>How to determine the inequality?</h3>

The complete question is added as an attachment

The points are given as:

(3, -2) and (2, 1)

Next, we test the points on each inequality in the list of options.

So, we have:

<u>Option 1</u>

y > 1/2x + 2

Substitute (3, -2) and (2, 1) for x and y

-2 > 1/2 * 3 + 2 ⇒ -2 > 3.5 -- false

2 > 1/2 * 1 + 2 ⇒ 2 > 2.5 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y > 1/2x + 2

<u>Option 2</u>

y <= 3/2x - 1

Substitute (3, -2) and (2, 1) for x and y

-2 <= 3/2 * 3 - 1 ⇒ -2 <= 3.5 -- true

1 <= 3/2 * 2 - 1 ⇒ 1 < 2 -- true

Hence, (3, -2) and (2, 1) are solutions to the inequality y <= 3/2x - 1

<u>Option 3</u>

y >= 4x - 2

Substitute (3, -2) and (2, 1) for x and y

-2 >= 4 * 3 - 2 ⇒ -2 >= 10 -- false

2 <= 4 * 2 - 2 ⇒ 2 <= 6 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y >= 4x - 2

<u>Option 4</u>

y < -2x + 1

Substitute (3, -2) and (2, 1) for x and y

-2 < -2 * 3 + 1 ⇒ -2 < -5 -- false

2 < -2 * 2 + 1 ⇒ 2 < -3 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y < -2x + 1

Read more about inequality at

brainly.com/question/24372553

#SPJ1

7 0
2 years ago
Name the solid and find its volume. Use 3.14 as the approximate value of pi.
sineoko [7]

It is given in the question that the solid is a cone with height of 16 units and radius of 7 units .

The formula of volume of cone is

V = \frac{1}{3} \pi r^2 h

To find the volume, we substitute the given values of r and h and use 3.14 for pi. That is

V = \frac{1}{3} *3.14*7^2 *16 = 820.6 \ units \ cube

And that's the required volume of the cone .

7 0
3 years ago
PLEASE HELP K12
BartSMP [9]

Answer:

<h2>15</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points (12, 6) and (12, -9). Substitute:

d=\sqrt{(12-12)^2+(-9-6)^2}=\sqrt{0^2+(-15)^2}=\sqrt{225}=15

7 0
3 years ago
Read 2 more answers
Help with my question please
nadezda [96]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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