Just got a 100 point question skim answered HA

If a×b×c=0 and a and b are integers greater than 10 what must equal c

myrzilka [38]

C is 0, since only multiplied by 0 will get 0, and the question defined that a and b not 0, so only c is 0

4 0

3 years ago

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20) Round each number to the nearest hundreds place.

xz_007 [3.2K]

Answer:

Step-by-step explanation:

X X X X . X X X

^ this is the hundreds place

X X X X . X X X

^ this is the hundredths place

a) 300 Because the place behind it is less than 5.

b) 1300 The place in the tens is 5 or greater.

c) 10,000 The place in the tens is 5 or greater which causes the 9 in the hundreds to go up which also causes the 9 in the thousands to go up as well.

d) 1,100

e) 700

6 0

3 years ago

If angle ASE measures 168. Find the measure of the angle DSE. The Figure may not be drawn to scale?

SpyIntel [72]

Alrighty, so, without the picture and the clues given I'm going to assume the image you have looks like two angles coming from the middle of a straight line. A straight line is equal to 180 degrees. 180 degrees minus 168 degrees equals 12.

7 0

3 years ago

Find the area under the standard normal curve to the left of z = 1.5

DaniilM [7]

Answer:

0.9332

Step-by-step explanation:

3 0

3 years ago

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Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

Statement 1: "The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

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Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

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Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

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Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

$178=x^2+3x-y\\ \\ -6=4x-3y$

8 0

3 years ago

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