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aalyn [17]
3 years ago
15

At what rate of interest would rs 1800 amount to rs 2500 in 2 years

Mathematics
1 answer:
Romashka [77]3 years ago
4 0

Interest formula: A = P(1 + rt)

Solving for r (Rate): r = (1/t)(A/P - 1)

Rate = (1/2)(2500/1800 - 1) = (1/2)(25/18 - 1) = (1/2)(7/18) = 7/36 ≈ 0.194

Rate = 0.194% per annum

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-2

Step-by-step explanation:

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Kira's chocolate bar is
erik [133]
The egation is 58/0.79=73
the cocoa ways 73% of the grams and 73% of 58 is 42 so the cocoa weighs 42 grams in total

6 0
2 years ago
Holly is taking out a loan in the amount of $10,000. Her choices for the loan are a 4-year loan at 4% simple interest and a 6-ye
notsponge [240]

Answer:

The difference in the amount of interest she would have to pay for the two loans is $1,400

Step-by-step explanation:

The amount of loan Holly is taking out, P = $10,000

The choices available for the loan are;

1) Loan duration, T₁ = 4-year

Interest rate, R₁ = 4%

2) Loan duration, T₂ = 6-year

Interest rate, R₂ = 5%

For the first choice, we have;

The simple interest, I, given by the formula;

I_1 = \dfrac{P \times  R_1 \times T_1 }{100} = \dfrac{10,000 \times  4 \times 4 }{100} = \$ 1,600

For the second choice, we have;

The simple interest, I, given by the formula;

I_2 = \dfrac{P \times  R_2 \times T_2 }{100} = \dfrac{10,000 \times  5 \times 6 }{100} = \$ 3,000

The difference, D, in the amount of interest she would have to pay for the two loans is therefore;

D = I₂ - I₁ = $3,000 - $1,600 = $1,400

The difference in the amount of interest she would have to pay for the two loans = D = $1,400.

7 0
3 years ago
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Which function describes the arithmetic sequence shown<br><br> -1, 1, 3, 5, 7, 9, 11, 13, ...
riadik2000 [5.3K]

Answer:

f(n) = 2n - 3 describes the arithmetic sequence,

-1, 1, 3, 5, 7, 9, 11, 13,.......

Step-by-step explanation:

Function:

A function is like a machine that gives an output for a given input.

A function has an independent variable which is called the input of the function.

The output for a given input is called the dependent variable.

Here. 'n' is the independent variable

f(n) is the function dependent variable i.e function of n as an output.

For Arithmetic sequence

a_{n}= a_{1} + (n-1)d

Where

a_{n} = nth number of the sequence.

a₁ = First term

d = common difference = a₂ - a₁ = a₃ - a₂ = so on

For a function which describes Arithmetic sequence,

a₁ = -1

d = 1 - -1 =2

∴ f(n) = a₁ + (n -1 )d

substituting the values we get

∴ f(n) = -1 +(n-1)2

using distributive property

∴ f(n) = - 1 +  2n - 2

∴ f(n) = 2n - 3  ..........is the required function

7 0
2 years ago
A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
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