There is a theorem in Geometry stating that the square of the tangent segment (ST) is equal to the product of the external secant segment (TR) and the whole secant segment (TQ).
SQ x SQ = TR x TQ
SQ squared = 7 x 30
SQ squared = 210
SQ =
William’s typical running speed is 6 mi/h. The difference between his fastest speed and his typical speed is 1.5 mi/h. The equat
2 answers:
You might be interested in
There is a theorem in Geometry stating that the square of the tangent segment (ST) is equal to the product of the external secant segment (TR) and the whole secant segment (TQ).
SQ x SQ = TR x TQ
SQ squared = 7 x 30
SQ squared = 210
SQ =
