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3 years ago

How do i solve this 4x-9=7x+12

Mathematics

2 answers:

zzz [600]3 years ago

6 0

Answer:

x = -7

Step-by-step explanation:

Combine like terms: (Subtract 4x from both sides, and subtract 12 from both sides)

4x - 9 = 7x + 12

-9 - 12 = 7x - 4x

-21 = 3x

Divide by 3:

-21 = 3x

x = -21 / 3

x = -7

Plug in to check your answer:

4x - 9 = 4(-7) - 9 = -37

7x + 12 = 7(-7) + 12 = -37

ddd [48]3 years ago

5 0

Answer:

x = -7

Step-by-step explanation:

4x - 9 = 7x + 12

~Add 9 to both sides

4x = 7x + 21

~Subtract 7x to both sides

-3x = 21

~Divide -3 to both sides

x = -7

Best of Luck!

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Help help help on this

pantera1 [17]

ANSWER

C. 2.402

EXPLANATION

Given that:

$log_{3}(2) = 0.631$

$log_{3}(7) = 1.771$

We want to evaluate:

$log_{3}(14) = log_{3}(2 \times 7)$

Use the product rule of logarithms.

$log_{a}(mn) = log_{a}(m) + log_{a}(n)$

$log_{3}(14) = log_{3}(2) + log_{3}(7)$

$log_{3}(14) = 0.631 + 1.771$

$log_{3}(14) = 2.402$

The third choice is correct.

7 0

3 years ago

What is the answer to 3. Y-7 over x-5 =2over 6

AysviL [449]

Answer: Y=9

X=11

Step-by-step explanation:

try this what number added by -7 = 2 think guess and check 9-7 =2

11-5=6

6 0

4 years ago

My grade is a 77%, if i get a 0% on a paper worth 30% of my grade, what will my grade be now??

blsea [12.9K]

$Grade=Paper+Other$
$Grade=(Grade_{paper}\times Value_{paper})+(Grade_{other}\times Value_{other})$
$Grade=(0 \times 30\%)+(77\% \times (1-30\%))$
$Grade=(0 \times 30\%)+(77\% \times 70\%)$
$Grade=0+53.9\%$
$Grade=53.9\%$

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4 years ago

One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fastt

mash [69]

Answer: $864\ m^2,\ 24\ m$

Step-by-step explanation:

Given

Perimeter of the rhombus is $120\ m$

Length of one of the diagonal is $d_1=36\ m$

All the sides of the rhombus are equal

$\Rightarrow 4a=120\\\Rightarrow a=30\ m$

Area of the rhombus with side and one diagonal is

$\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}$

Insert the values

$\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2$