Solve for the unknown values. 95 х 50 у degrees y = degrees

Classify What type of number is 1.00 repeating

sveticcg [70]

Answer:

rational, integer, whole, natural, real

Step-by-step explanation:

Trailing zeros after the decimal point do not change the value of a number. This number is 1, a rational, real, integer, whole, natural number.

7 0

3 years ago

Susie lost $15 on Monday. Her mom was upset, but gave her another $20. She lost another $13 today. Write an integer to represent

maria [59]

Answer:

Step-by-step explanation:

If you add 13 +15 you get 28$ if we were to write that as an integer out of 20 it would be 28/20 but as an improper fraction, it would need to be simplified into 1 and 8/20 ( 1 8/20)

If you are looking how much she lost out of the 20 she lost today it would be 13/20

Hope this helps

Dont lose ur money

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4 0

2 years ago

Helppp which one is it pleasee

solong [7]

Answer:

I think is D because u are putting the opposite in the first solutions u got a positive equation so for the other solutions i think u maybe are going to got the opposite I may be wrong But I just trying to help so sorry if u got it wrong

4 0

3 years ago

Simplify ‐19 ‐ 7( ‐17z + 13) 4n ‐ 3( ‐9n + 13)

nataly862011 [7]

Answer:

for the first one it's 119z−110

the second one is 31n−39

i'm not sure if you wanted both together

so here just incase

31n+119z−149

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

A Packaging Company produces boxes out of cardboard and has a specified weight of 16 oz. A random sample of 36 boxes yielded a s

user100 [1]

Answer:

The margin of error is of 0.73 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.575\frac{1.7}{\sqrt{36}} = 0.73$

The margin of error is of 0.73 oz.

The lower end of the interval is the sample mean subtracted by M. So it is 15.3 - 0.73 = 14.57 oz.

The upper end of the interval is the sample mean added to M. So it is 15.3 + 0.73 = 16.03 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

4 0

2 years ago