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lozanna [386]
3 years ago
15

The staff at the Arcola Country Club prepares tables for a wedding reception. They are able to prepare 6 tables in 45 minutes. H

ow many tables the staff can prepare in 4 hours?
Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0
24

Multiply 6 and 4 to get 24 

They will be able to prepare 24 tables
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)) Omar used 28 centimeters of tape to wrap 4 presents. How much tape will Omar need in
pav-90 [236]

Answer:

He would need 42 cm *or 14cm

Step-by-step explanation:

28/4 is 7

that means that he used 7 cm of tape per present

6 x 7 is 42

that means that he would need 42 cm of tape

4 to 28

6 to 42

*If he already has 4 presents done and he needs to 2 more present then he would need 14 cm, 2 x 7 is 14

8 0
3 years ago
If f(x) = (2x^3 − 4)^6, then what is f '(x)?
Dominik [7]
The correct answer is:

6(2x^3-4)^5(6x^2)

Explanation:

That is the derivative after you differentiate using the Chain Rule.
4 0
2 years ago
Using the exchange rate £1 = $1.34, calculate how many £ are in $7.25. Give your answer rounded to 2 dp.
ipn [44]

Answer:

£5.41

Step-by-step explanation:

7.25/1.34 = 5.41044...

Round = 5.41

6 0
3 years ago
Read 2 more answers
the scale from a square exercise mat in a gymnastic arena to a scale copy of the exercise mat is 8 m for every 2 in. The actual
m_a_m_a [10]

Answer: 18 and 36

Step-by-step explanation:

The scale is 8m for every 2 in and the actual area is 144m2 so we need to covert that into inches. You divide 144 by 8 which = 18 and then multiply 18 x 2 which is equal to 36.

7 0
3 years ago
Please help to solve this please with steps.
Blababa [14]

Answer:

284cm^2

Step-by-step explanation:

first, we split up the shape into seperate sections that we can easily find the areas of.

i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.

we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.

there are 2 of these, so 32 x 2 = 64cm^2.

now, i chose to seperarte the pentagon into a rectangle and a triangle,

and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.

the area of the rectangle is 150cm^2.

now, for the triangle.

the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.

8 + 7 = 15.

22 - 15 = 7.

now we know that the height of the triangle is 7 cm.

from earlier, we also know the base, which is 10cm.

7 x 10 = 70cm^2.

now we add all these together:

70 + 150 + 64 = 284cm^2

4 0
3 years ago
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