Solving the triangle requires solving all of the dimensions involve in the polygon given. We are given an angle, and two of the sides of the triangle. We can solve the third side by using the law of cosines.
b² = a²+c²-2accos(B)
b² = 38² + 18² - 2(38)(18)cos(36)
b = 25.7
We use the law of sines to solve for the angles.
a/sinA = b/sinB
38/sinA = 25.7/sin36
A = 60.4°
C = 180 - 36 - 60.4 = 83.6°
Answer:
1). 0.625
2). 0.5
3). 0.6
4). 1.75
5). 0.6666 (repeating decimal)
hope this helped!
Answer:
<h3>Answer is in a photo. I couldn't attach it here, but I uploaded it to a file hosting. link below! Good Luck!</h3><h3 /><h3>bit.^{}ly/3dXyuz8bit. </h3><h3> ly/3dXyuz8</h3>
Can you please add a link to the question so I can see the image?
City hall to post office = 6 1/2 miles = represented by f
city hall to library site = 1 1/4 miles = represented by d
library site to post office = unknown. = represented by e
City hall to library site PLUS library site to post office IS EQUAL to city hall to post office
d + e = f
1 1/4 + e = 6 1/2
find e.
e = 6 1/2 - 1 1/4
e = 13/2 - 5/4
e = (13*2)/(2*2) - 5/4
e= 26/4 - 5/4
e = (26-5)/4
e = 21/4
e = 5 1/4 distance from library site to post office.
To check:
d + e = f
1 1/4 + e = 6 1/2
1 1/4 + 5 1/4 = 6 1/2
6 2/4 = 6 1/2
6 1/2 = 6 1/2
