The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
Isolate the variable x.
1-2x=-x-3
1=x-3
x=4
We know that
the law of sines establish
a/sin A=b/sin B
problem N 1
50/sin K=53/sin 76-------> 50*sin 76=53*sin K-----> sin K=50*sin 76/53
sin K=0.9154
K=arc sin (0.9154)--------> K=66.25°------> K=66°
the answer problem N 1 is the option
<span>c.) 66°
</span>
Problem N 2
30/sin R=35/sin 69------> sin R=30*sin 69/35-----> sin R=0.8002
R=arc sin(0.8002)-------> R=53.15°-----> R=53°
the answer problem N 2 is the option
<span>b.) 53°</span>
Answer: a
Step-by-step explanation: look at the chart
Answer:
7.5
Step-by-step explanation: