Maybe 88 not sure that is the givin
Answer:
The answer is below
Step-by-step explanation:
We need to prove that:
(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.
Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.
Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

Answer:
The probability that the first marvel will be red and the second will be green is 7.14%.
Step-by-step explanation:
Since a bag contains 2 red marbles, 2 green marbles and 4 blue marbles, if we choose a marble and then other marble without putting the first one back in the bag, to determine what is the probability that the first marvel will be red and the second will be green, the following calculation must be performed:
2 + 2 + 4 = 8
2/8 x 2/7 = X
0.25 x 0.2857 = X
0.0714 = X
Therefore, the probability that the first marvel will be red and the second will be green is 7.14%.