Answer: 300 m
<u>Step-by-step explanation:</u>
![distance(s)=v_it+\dfrac{1}{2}at^2 \quad \text{where}\ v_i \text{is initial velocity, a is acceleration, t is time}](https://tex.z-dn.net/?f=distance%28s%29%3Dv_it%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2%20%5Cquad%20%5Ctext%7Bwhere%7D%5C%20v_i%20%5Ctext%7Bis%20initial%20velocity%2C%20a%20is%20acceleration%2C%20t%20is%20time%7D)
![s=(15)(10)+\dfrac{1}{2}(3)(10)^2](https://tex.z-dn.net/?f=s%3D%2815%29%2810%29%2B%5Cdfrac%7B1%7D%7B2%7D%283%29%2810%29%5E2)
= 150 + 150
= 300
Answer: Y=-1/4x
Step-by-step explanation:
A good way to find an equation of a line is to look for the slope. An obvious spot on this line would be when it crosses (0,0), and another one to the right would be when it crosses at (4,-1).
The slope is rise over run, or if we use the two points we found, "rise" would be -1, because it's dropping 1 unit when going from (0,0) to (4,-1), and the "run" would be 4, because it moves to the right 4 from (0,0) to (4,-1).
Putting these two values together we get:
m (slope) = rise / run
m = -1 / 4
Out of all the equations we're given, we can look for the one with a slope of -1/4, which is given to us:
y = (-1/4)x
The domain and range for each line is all real numbers. This is because all numbers are possible to input into x and all y values exist.
The slope of the first line is -2/3 and the y intercept is 6. You can reach this conclusion by solving for y (putting it in slope intercept form).
The slope of the second one is 3/4. and the y intercept is all real numbers greater than -4. This is true because it is an inequality and you can find these numbers by solving for y.
X=147
Angle x and 33 are a linear pair meaning they equal 180 and 180-33=147