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Katarina [22]
3 years ago
14

Please help i need this

Mathematics
2 answers:
Contact [7]3 years ago
8 0

Answer:

13

Step-by-step explanation:

because you have to divide 13 divide by 1 and eat equals 13 then if you spin it the posibility might be 13

Dovator [93]3 years ago
6 0

Answer:

7/13

Step-by-step explanation:

Given;

A spinner has 13 equal sections.

Find;

The probability of landing on an odd number.

1. Information that one needs to know

To calculate the probability, one needs to have the number of favorable outcomes over the total number of outcomes.

2. Solving the problem

The favorable outcomes are the odd numbers, hence one needs to find the number of odd numbers between 1 and 13. There are 7 odd numbers between 1 and 13. The total number of outcomes is 13, hence the probability of landing on an odd number is 7/13.

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What is the value of x in the equation three-fifths x = negative 45? –75 –27 27 75
scoundrel [369]

Answer:

x = -75

Step-by-step explanation:

\frac{3}{5} x = - 45 ( multiply both sides by 5 to clear the fraction )

3x = - 225 ( divide both sides by 3 )

x = - 75

8 0
2 years ago
Read 2 more answers
WILL IVE BRAINLIEST IF CORRECT AND HURRY A rectangle has an area of 77 square inches and a width of 5.5 inches.
sattari [20]
The length of “L” is 14.

Hope this helps you!!
4 0
2 years ago
Read 2 more answers
2. Show work on how to solve for the following equation, and check your solution -5 2x-3 4 5x-5​
andriy [413]

Answer:-397x+-5

Step-by-step explanation:

-52x-345x-5

=-52x+-345x+-5

=(-52x+-345x)+(-5)

=-397x+-5

6 0
3 years ago
Find the area of quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21)
sasho [114]

Answer:

The area of quadrilateral ABCD is 139 unit^2.

Step-by-step explanation:

Given:

Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).

Now, to find the area.

The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).

So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:

In Δ ABC:

A(x_1,y_1)=(1,1)\:,\:B(x_2,y_2)=(7,-3)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ABC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-3-2)+(7)(2-1)+12(1--3)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-5)+(7)(1)+12(4)\right|

On solving we get:

Area\,of\,triangle\,=25.

In Δ ADC:

A(x_1,y_1)=(1,1)\:,\:D(x_2,y_2)=(7,21)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ADC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(21-2)+(7)(2-1)+12(1-21)\right|

On solving it by same process as above we get:

Area\,of\,triangle\,=114

Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:

25+114\\=25+114\\=139\ unit^2

Therefore, area of quadrilateral ABCD is 139 unit^2.

4 0
3 years ago
Geometry question PLS HELP!!!!!!!!111
SOVA2 [1]
5k-3+9+k=180
6k+6=180
6k=174
k= 174/6= 29

2(180-2h)+40=180
360-4h=140
4h=360-140=220
h=55
5 0
3 years ago
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