Answer:
BC < CE < BE < ED < BD
Step-by-step explanation:
In the triangle BCE,
m∠BEC + m∠BCE + m∠CBE = 180°
m∠BEC + 81° + 54° = 180°
m∠BEC = 180 - 135
m∠BEC = 45°
Order of the angles from least to greatest,
m∠BEC < m∠CBE > mBCE
Sides opposite to these sides will be in the same ratio,
BC < CE < BE ----------(1)
Now in ΔBED,
m∠BEC + m∠BED = 180°
m∠BED = 180 - 45
= 135°
Now, m∠BDE + m∠BED + DBE = 180°
11° + 135°+ m∠DBE = 180°
m∠DBE = 180 - 146
= 34°
Order of the angles from least to greatest will be,
∠BDE < ∠DBE < ∠BED
Sides opposite to these angles will be in the same order.
BE < ED < BD ----------(2)
From relation (1) and (2),
BC < CE < BE < ED < BD
Answer:
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Step-by-step explanation:
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Your question is very vague, there is no multiple choice answers, your question lacks basically everything.
-2+(-2=4?
Answer:
The solution is 
.
Step-by-step explanation:
A first order differential equation 
is called a separable equation if the function 
can be factored into the product of two functions of 
and 
:
where 
and 
are continuous functions.
We have the following differential equation
In the given case 
and 
.
We divide the equation by and move 
to the right side:
Next, integrate both sides:
Now, we solve for
We use the initial condition 
to find the value of C.
Therefore,
