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Leto [7]
3 years ago
7

What is the answer to a and b? pls help

Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0

Step-by-step explanation:

A is 6/10 inches

B is 0.60 inches

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Find the value of x for this figure
Lera25 [3.4K]

Answer:

x = 101°

Step-by-step explanation:

15 + 25 + 39 + x = 180

79 + x = 180

x = 101

8 0
3 years ago
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If 55% of the students in a certain college are female and there are 1,452 female students, what is the total number of students
Len [333]

Answer:

So 55% of an unknown number is 1452

Let this unknown number be n

Then 55% of n = 1452

We now solve for n

55% × n = 1452

55/100 × n = 1452

0.55 × n = 1452

n = 1452/0.55

n = 2640

Therefore there are 2640 students in the college

8 0
3 years ago
On the first day of the fiscal year, Shiller Company borrowed $85,000 by giving a seven-year, 7% installment note to Soros Bank.
Lera25 [3.4K]

Answer

A₁ - Journal entry at the time of issue of installment note for cash:

Bank A/c                              Dr           $85,000

To Notes Payable               Cr           $85,000

A₂– Journal entry at the time of first annual payment:

Notes Payable A/c           Dr           $9,822

Interest Expense A/c       Dr           $5,950

To Bank A/c                   Cr                            $15,772

Notes payable to be reported in balance sheet at the end of fiscal year:

Notes payable end balance = $85,000 - $9,822 = $75,178

Interest for 2nd year = $75,178 * 7% = $5,262

Installment amount for 2nd year = $15,772  

Principal repayment for 2nd year = $15,772 - $5,262 = $10,510

Therefore out of $75,178 notes payable, $10,510 is payable within 1 year.

There $10510 will be shown in balance sheet as current liabilities and

remaining $64,668 will be shown in balance sheet as long term liability.

5 0
3 years ago
A student reduces the temperature of a 300 cm3 balloon from 60°C to 30°C. What will the new volume of the balloon be? (Remember
amid [387]
Assuming constant pressure, V/T = constant.

Where T is absolute temperature, and V is volume.

T1 = 60 ° + 273.15 = 333.15 K
V1 = 300 cm^3

T2 = 30°C + 273.15 = 303.15 K
V2 = ?

V1 / T1 = V2 / T2 = >  V2 = [V1/T1] * T2

V2 = [300cm^3 / 333.15K] * 303.15K = 272.9 cm^3

Answer: 272.99 cm^3
4 0
3 years ago
Consider F and C below. F(x, y, z) = 2xz + y2 i + 2xy j + x2 + 9z2 k C: x = t2, y = t + 3, z = 3t − 1, 0 ≤ t ≤ 1 (a) Find a func
Ray Of Light [21]

Answer:

a)∇f = 2y + 2x + 18z

b) \int\limits^._C {F} \, dr =108

Step-by-step explanation:

Given:

f (x,y,z ) = (2xz+ y^{2})i + (2xy) j +(x^{2} + 9z^{2})k

The curve C :

x=t^{2} ,\\y= t+3\\z= 3t-1

where 0 ≤ t ≤ 1

Required:

(a) F = ∇f =? (F is a vector here)

(b) \int\limits^._C {F} \, dr =?

Solution

First we will find the directional derivative F = ∇f

for that , we will use the formula :

∇f = F_{x}i+ F_{y} j+F_{z}k

Fx= δf/δx = δ/δx (2xz+ y^{2})i = 2z i

Fy= δf/δy=δ/δy (2xy)j = 2x j

Fz= δf/δz=δ/δz(x^{2} + 9z^{2})k = 18z k

∇f = (2z) i .i + (2x) j.j + (18z) k.k

∇f = 2z + 2x + 18z

<em>For part b):</em>

<em>we will use line integral formula:</em>

\int\limits^._C {F} \, dr

to calculate dr, we will need the curve C:

r = x(t)+y(t)+z(t)

r=(t^{2})i + (t+3) j +(3t-1) k

\frac{dr}{dt}=\frac{dx}{dt} +\frac{dy}{dt} + \frac{dz}{dt}

\frac{dx}{dt} = 2t

\frac{dy}{dt} = 1

\frac{dz}{dt} = 3

\int\limits^._C {F} \, dr = \int\limits^1_0 {F_{x} } \, dx+ F_{y} dy +F_{z} dz

= \int\limits^1_0 {(2z(2t) + 2x(1) + 18z (3)} \, )

put values of y, x and z

= \int\limits^1_0 {2(3t-1) + 2(t^{2}) +18 (3) (3t-1)} \,

={2t^{2} + 6t+162t -54-2}\, |^1_0

={ 2t^{2}+ 168t - 56} \,|^1_0               (Note : f(1)-f(0))

=2(1)+162(1)+2(0)+162(0)-56

= 2+162 -56

\int\limits^._C {F} \, dr =108

3 0
3 years ago
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