Assuming the order required is as n-> inf.
As n->inf, o(log(n+1)) -> o(log(n)) since the 1 is insignificant compared with n.
We can similarly drop the "1" as n-> inf, the expression becomes log(n^2+1) ->
log(n^2)=2log(n) which is still o(log(n)).
So yes, both are o(log(n)).
Note: you may have more offers of answers if you post similar questions in the computer and technology section.
For the first equation, the answer is C) completing the square.
For the second equation, the answer is B) zero product property.
For the first equation, we can easily complete the square by finding half of b and squaring it; then we can take the square root of both sides and solve the equation.
For the second equation, since it is already factored, we use the zero product property to solve it.
Step-by-step explanation:
A simple event is one that can only happen in one way - in other words, it has a single outcome. If we consider our previous example of tossing a coin: we get one outcome that is a head or a tail. A compound event is more complex than a simple event, as it involves the probability of more than one outcome.
Answer:
2774
Step-by-step explanation:
start by multiplying 2 by 7, the answer is 14 put the 1 above the 8 in 1387 then put the 4 under the equation, similar to addition. repeat but next time when you multiply 2 by 8 add the 1 (from the previous multiplication) to the answer under and put the 1 from 17 on top of the 3. you get it?
Answer:
98
Step-by-step explanation:
10-3=7
7x7=49
49 x2 = 98
Have a good day! uwu
