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Hatshy [7]
3 years ago
10

the light bulbs you use are on sale. but you only get the lower price if you buy 3 packsages of bulbs. you want to know how much

you'll save. write a formula that will help you determine how much you'll save by buying 3 packages on sale. s=sale price per package r=regular price per package c=cost saving
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0
(R*3)-(S*3)=C
The regular price of 3 light bulbs minus the sale price of 3 lightbulbs equal the amount you will save on 3 lights
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Answer:

1. 540 sq. ft.   2. 7,200 sq. m.   3. 276 sq. yd.   4. 6,000 sq. mm.

Step-by-step explanation:

You find the area of a parallelogram by doing the same as you would a rectangle, multiplying length by width. (If you imagine slicing off the triangle shape on the end of all of these and putting it on the other side, it will always make a rectangle.)

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Given g(x) = - 4x + 4, find g(3).<br> Answer:
likoan [24]

Answer:

-8

Step-by-step explanation:

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4 0
2 years ago
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write and solve the differential equation that models the following statment. "the rate if change of W with respect to x is prop
Vaselesa [24]

Answer:

\int k(x + 18)dx = \int kx + 18k dx = k\frac{x^{2} }{2} + 18kx + C where C is the constant of integration.

Step-by-step explanation:

i)it is given that the rate of change of W with respect to x is proportional to          

     x + 18. Therefore \frac{dW}{dx} = k(x + 18) where k is a constant.

ii) Therefore \int k(x + 18)dx = \int kx + 18k dx = k\frac{x^{2} }{2} + 18kx + C where C is the constant of integration.

iii) the complete solution can only be found if we know the constant of proportion and also the constant of integration.

4 0
3 years ago
Helpi accendintly made the question I just posted 5 points but this one is 50
Umnica [9.8K]

(a) For any probability distribution, the total probability must be 1. That is, the area under the probability density curve must be equal to 1.

The empirical rule for normal distributions says

• approximately 68% of the distribution lies within 1 standard deviation of the mean

• approx. 95% lies within 2 s.d. of the mean

• approx. 99.7% lies within 3 s.d. of the mean

In this case, with mean 3500 and s.d. 470, this translates to

• Pr(3500 - 470 < X < 3500 + 470) = Pr(3030 < X < 3970) ≈ 0.68

• Pr(3500 - 2*470 < X < 3500 + 2*470) = Pr(2560 < X < 4440) ≈ 0.95

• Pr(3500 - 3*470 < X < 3500 + 3*470) = Pr(2090 < X < 4910) ≈ 0.997

Continuous probability distributions also have the property that

Pr(a < X < b) = Pr(a < X < c) + Pr(c < X < b)

if a < c < b.

Combining all these properties, we can find the probabilities for each of the 8 regions in the graph to be (from left to right)

• Pr(-∞ < X < 2090) ≈ (1 - 0.997)/2 ≈ 0.0015

• Pr(2090 < X < 2560) ≈ (1 - 0.95 - 2*0.0015)/2 ≈ 0.0235

• Pr(2560 < X < 3030) ≈ (1 - 0.68 - 2*0.0235 - 2*0.0015)/2 ≈ 0.135

• Pr(3030 < X < 3500) ≈ 0.68/2 ≈ 0.34

and since the distribution is symmetric about its mean, we already know the remaining probabilities,

• Pr(3500 < X < 3970) ≈ 0.34

• Pr(3970 < X < 4440) ≈ 0.135

• Pr(4440 < X< 4910) ≈ 0.0235

• Pr(4910 < X < ∞) ≈ 0.0015

(b) Per the rule, 99.7% of babies would weight between 2090 and 4910 grams.

(c) The proportion of babies weighing less than 3030 grams is the sum of the proportions of babies weighing less than 2090, between 2090 and 2560, and between 2560 and 3030 grams. So

Pr(X < 3030) = Pr(-∞ < X < 2090) + Pr(2090 < X < 2560) + P(2560 < X < 3030)

Pr(X < 3030) ≈ 0.0015 + 0.0235 + 0.135

Pr(X < 3030) ≈ 0.16 = 16%

(d) Similarly,

Pr(X > 2560) = Pr(2560 < X < 3030) + Pr(3030 < X < 3500) + … + Pr(4910 < X < ∞)

Pr(X > 2560) ≈ 0.135 + 0.34 + 0.34 + 0.135 + 0.0235 + 0.0015

Pr(X > 2560) ≈ 0.975 = 97.5%

8 0
2 years ago
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