Answer:
12
Step-by-step explanation:
The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
Answer:
C = 2πr
Step-by-step explanation:
We know that, the perimeter of a figure is equal to the sum of all sides.
A circle having no sides.
The perimeter of a circle = The circumference of the circle
The formula for the circumference of the circle is given by :
C = 2πr
Where
r is the radius of the circle
Hence, this is the required solution.
Step-by-step explanation:
8(b+1)=-3(2+b)
8b+8=-6-3b
8b +3b = -6-8
11b = -14
b = -14/11
Answer:
Tooth A
Step-by-step explanation:
Since the larger tooth has to be displayed, knowing that no matter how many zeros you add to the end of a decimal, the value of it will stay the same. 0.23 is 1 digit short that 0.195, so if you just add a 0 to 0.23, it make both of them have a digit in the thousandths place. Now it's easier to solve, 0.230>0.195.
Tooth A should be displayed.